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  1. Thought blocker

    Mathematics: Post your doubts here!

    Kindly upload it :/
  2. Thought blocker

    Busy person. :/

    Busy person. :/
  3. Thought blocker

    Mathematics: Post your doubts here!

    Was it that easy O.o ? Ty :D
  4. Thought blocker

    Mathematics: Post your doubts here!

    You think I'll do the same, then no need. I'll get it solved by others. Indeed. Suchal Riaz ZaqZainab sitooon midha.ch Adeena Shamshir :p
  5. Thought blocker

    Lol, yup.

    Lol, yup.
  6. Thought blocker

    :'P

    :'P
  7. Thought blocker

    Mathematics: Post your doubts here!

    :(
  8. Thought blocker

    same name :P

    same name :P
  9. Thought blocker

    Mathematics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s13_qp_12.pdf Question 2ii) , 4i),iii) , 5i), 6i), 7, 8i,ii) Please. Some questions I am just stuck on formula like :¬ in question 4 i) dont we use : theta = cos inverse a^2 + b^2 - c^2...
  10. Thought blocker

    Mathematics: Post your doubts here!

    Q4) Q8) i) given, f(0)=-1 so, a + bcos2(0) = -1 ; a + b(1) = -1 given f(pie/2) = 7, a + bcos2pi/2 = 7 ; a + b(-1) = 7 solve siml. eqn, you get a = 3 and b = -4. ii) Put the values : 3 - 4cos2x = 0 cos2x = 3/4 cos inverse 3/4 = 0.722 2x = 0.722 x = 0.36 and see the domain hence, pi - 0.36 you...
  11. Thought blocker

    i see

    i see
  12. Thought blocker

    O.o

    O.o
  13. Thought blocker

    Boardworks ppt for Physics A Level (AS and A2)

    Practicals or paper 2 ?
  14. Thought blocker

    Bye.

    Bye.
  15. Thought blocker

    I aint at my home today [103406:Adeena Shamshir] , I am out with ma father, and dharm will come...

    I aint at my home today [103406:Adeena Shamshir] , I am out with ma father, and dharm will come at your house.
  16. Thought blocker

    ty

    ty
  17. Thought blocker

    Mathematics: Post your doubts here!

    part i) To find f inverse, convert f(X) to x and x to y so, x = (root of y + 3 / 2 ) + 1 = ( x - 1 ) => (root of y + 3 / 2 ) = 2(( x - 1 )^2) -3 => y Now convert y = f inverse. when you open the bracket you get is 2x^2 - 4x - 1 part ii) (NOTE >= means greater or equal to) Range of F(X) is...
  18. Thought blocker

    Mathematics: Post your doubts here!

    (1-(sin^2x/cos^2x)) --------------------------- = (1+(sin^2x/cos^2x)) (cos^2x-sin^2x) -------------------------- (cos^2x+sin^2x) Now, Using the identity , if we subtract from both sides, we obtain so, 1-2sin^2x / 1 = 1-2sin^2x ;)
  19. Thought blocker

    good

    good
  20. Thought blocker

    :P

    :P
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