• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. Thought blocker

    Mathematics: Post your doubts here!

    I dont know this method is correct or not :p We had to show a point of reflection, hence we have x1,y1 as (-1,3) and we found a midpoint (3,9) by sim. equation, So, as to find midpoint we do (x1+x2)/2, and (y1+y1)/2, similarly, We know have to find x2 and y2, we have x1 y1 and midpoint :) so...
  2. Thought blocker

    Mathematics: Post your doubts here!

    Wait lemme send you again..
  3. Thought blocker

    Tomorrow is Math, Chemistry and English, Dammit!

    Tomorrow is Math, Chemistry and English, Dammit!
  4. Thought blocker

    Mathematics: Post your doubts here!

    I said you na... Din't you got me ?
  5. Thought blocker

    -.P

    -.P
  6. Thought blocker

    Legends

    Legends
  7. Thought blocker

    Mathematics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w12_qp_12.pdf
  8. Thought blocker

    ty u 2 :)

    ty u 2 :)
  9. Thought blocker

    Bio yes.

    Bio yes.
  10. Thought blocker

    Wow, telepathy ;)

    Wow, telepathy ;)
  11. Thought blocker

    O.o

    O.o
  12. Thought blocker

    Mathematics: Post your doubts here!

    2013 and 2009 may june was tough for me :p
  13. Thought blocker

    Mathematics: Post your doubts here!

    come here : http://www.twiddla.com/1610154
  14. Thought blocker

    Mathematics: Post your doubts here!

    Sorry I can't now I have to finish two chapters of chem, so sorry. @suchal help him too :)
  15. Thought blocker

    Mathematics: Post your doubts here!

    GCE As and a level 4i) (x/k)+k = x^2/4 =>4((x/k)+k) = x^2 =>4x/k=x^2-4k =>4x = kx^2 - 4k^2 =>kx^2-4x-4k^2 = 0 Use b^2 - 4ac = 0 16 +16k^3 = 0 k = -1 :) 4ii) kx^2-4x-4k^2 = 0 put k as -1 and get your x value as -2 now as we have y = x^(2)/4 put 2 as x, you get y as 1 so P is (-2,1) :) 6ii)...
  16. Thought blocker

    When did I not replied :o ?

    When did I not replied :o ?
  17. Thought blocker

    you. :/

    you. :/
  18. Thought blocker

    I too dk, but jlt :P

    I too dk, but jlt :P
  19. Thought blocker

    Nah, in dreams. :P

    Nah, in dreams. :P
  20. Thought blocker

    Mathematics: Post your doubts here!

    Sure :)
Top