• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. sidbloom1995

    Chemistry: Post your doubts here!

    im sorry but im not confident enough to post my answer without confirmation! i'll tell you the answer and if it is right, i'll post the procedure! it's CHO just!
  2. sidbloom1995

    Chemistry: Post your doubts here!

    O/N 2010 -11- Q29. (sorry i didnt see it before) the ans is C because we will have 3 structures 2 will be from -cis and -trans one will be a simple carbon chain of 4 carbons, butene! Q35. sorry i dont know for 3 in this i'll tell u about it if i find anything!
  3. sidbloom1995

    Chemistry: Post your doubts here!

    can you post the MS! thanks :)
  4. sidbloom1995

    Chemistry: Post your doubts here!

    seondary structure consist of hydrogen bondings being formed between -CO and -NH group they form either alpha helix of beta plated structures the tertiary structure consist of 4 types of bondings 1. Hydrogen bonging 2. ionic bond between opositely charged groups 3. van der waals forces between...
  5. sidbloom1995

    Chemistry: Post your doubts here!

    except for 37 i answered the rest of them did you not understand the explanation?
  6. sidbloom1995

    Chemistry: Post your doubts here!

    O/N 2010 -12- Q13. Answer is B the balancing of our equation is 5HIO ---------> 2[I2] + 1 [HIO3] + 2[H2O] thus our answer will be B Q27. this one im not entirely sure of the reasoning the answer is A because our compound is an ester and with treatment to acid, the ester breaks to carboxylic...
  7. sidbloom1995

    Chemistry: Post your doubts here!

    O/N 2006 Q3. C they gave us a total of 4 elements and 4 choices....the rest of the three choices belong to Ca P and Kr and the last one belongs to X so after you have figured out the configuration fro the rest the remainder is your answer! O/N 2007 the ans is D because the X axis says "the no...
  8. sidbloom1995

    Chemistry: Post your doubts here!

    i see thanks :)
  9. sidbloom1995

    Chemistry: Post your doubts here!

    i have a doubt! the reddish brown color of iodine is due to I2 or I- ???
  10. sidbloom1995

    Chemistry: Post your doubts here!

    is that for the answer or for informing you that it is A level post? -_-
  11. sidbloom1995

    Chemistry: Post your doubts here!

    you have to look at the data provided in the table if you notice, the amount of mass deposited on the cathode is 0.12 g for exp. 1 in reaction 2, the current is doubled so the mass deposited will also double thus out mass in exp. 2 is 0.24 g in exp. 3, the time is doubles but the current is...
  12. sidbloom1995

    Chemistry: Post your doubts here!

    they said that the gas is evolved and to check the identity of the gas, they tested it with filter paper dipped into acidified potassium dichromate(VI), and the colour changed from orange to green. this is particularly the test for SO2 gas and it's result tell us that the gas evolved it SO2 i...
  13. sidbloom1995

    Chemistry: Post your doubts here!

    can you please post the MS I need to make sure of my answers before giving them thank you :)
  14. sidbloom1995

    Chemistry: Post your doubts here!

    Q1. the mass that is given is the mass of Ag so use it to find out the moles of Ag n of Ag = 0.216/108 = 2 x 10^-3 now multiply this with avagadro's constant to find the no. of atoms in this much mass (or moles) of Ag no. of atoms of Ag present = [2 x 10^-3] X [6.02 x 10^23] = 1.204 x 10^21 now...
  15. sidbloom1995

    Chemistry: Post your doubts here!

    yes the restriction is there because of pi-bond think of it as a ball and it is inserted with a stick like in lollipop....but not stuck so if you spin it, it will spin in it's place but now if you attach two sticks with it, the ball wont spin any more because if it tries to rotate around one...
  16. sidbloom1995

    Chemistry: Post your doubts here!

    you can try on youtube i searched it and found a very good video recently just type NMR spectroscopy and you will get a bunch of options, choose the one from the user Leah Fisch
  17. sidbloom1995

    Chemistry: Post your doubts here!

    i fouund the answer to part (iv) benzene rings form rigid structures and make the polymer less flexible so in order to make it flexible, make it into a cyclic acid or remove the double bond in the benzene
  18. sidbloom1995

    Chemistry: Post your doubts here!

    (iii) since our polymerisation is condensation polymerisation and our E and F are phenol and carboxylic acid, we have ester linkage! phenol will react much more readily with acyl chloride then with carboxylic acid and will give a higher yield so we will first convert carboxylic acid to acyl...
  19. sidbloom1995

    Chemistry: Post your doubts here!

    i hope this helps!
  20. sidbloom1995

    Chemistry: Post your doubts here!

    i hope this helps if not then you can still ask again :P (but i hope you get it this time) ;)
Top