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Ouch.

Get cape. Wear it. Fly..

I think 25 or 26. #SayNoToEarlyMarriage. :p They should get married when they know they can do something for themselves in their life.

Put any value of x you'll get a positive result. Why? Because the squared term of both the expressions is positive. You can even use your sketching skills to show.

Hahaha. Oops. Its okay. Youll get 5x/12 as the middle term with that. (y) You're welcomee! ;)

HAHAHAHA. ohhhhh :p

Okay so here it is: Bring the denominators up. 3(3 + 2x)^(-1) + (-x – 2)[(x^2 + 4)^(-1)] Expand. 3(3 + 2x)^(-1) + [-x (x^2 + 4)^(-1)] – [2((x^2 + 4)^(-1)] You need to separately expand : (3 + 2x)^(-1) & (x^2 + 4)^(-1) So, (3 + 2x)^(-1) = 3^(-1)[1 +2x/3]^(-1) = 1/3 (1 + 2x/3)^(-1) 1/3...

tell me ur ans to i :p

you arent giving the redesigned one. are you? :p

Indecisiveness.....

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Which city?

No more than a passing fancy..

ii) Maximum point. Put dy/dx = 0 dy/dx ; y = e^(2sinx) * cosx u = e^(2sinx) u’ = 2cosx*e^(2sinx) v = cosx v’ = -sinx dy/dx = uv’ + vu’ 0 = [e^(2sinx)* -sinx ] + [cosx*2cosx*e^(2sinx)] 0 = e^2sinx [-sinx + 2cos^2(x)] 0 = -sinx + 2cos^2(x) Sinx = 2(1 – sin^2(x)) sinx= 2 – 2sin^2(x)...

Dy/dx = 6ye^3x/(2+e^3x) Dy/y = 6e^3x/(2+e^3x)dx ʃ dy/y = ʃ 6e^3x/(2+e^3x)dx lny = 6 ʃ e^3x/(2+e^3x)dx lny = 6 (1/3)ln(2+e^3x) + C Now you have y = 36 and x = 0. Use them to find C. ln36 = 2ln(2+e^3(0)) + C ln36 = 2 ln(2 +1) + C ln36 = 2ln3 + C ln 36 = ln3^2 + C ln 36 =ln9 + C ln36 –...

Sure. 5 minutes :D

Oh wait. That k is a constant neha. They have just written k instead of the answer. I got 2ln(2 plus e^3x) So k is basically 2. Dont get confused. If you want me to solve it then I will.... ?