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  1. asd

    Mathematics: Post your doubts here!

    q10 part 1 for oct/nov (Lim from 0 to 1) Int(u^(n+2) + u^n) converting the limits, tan(pi/4)= 1 tan(0)=0 converting dx into du, u=tanx => du/dx= sec^2(x)= 1+tan^2(x) dx= du/1+u^2 Now, lim(0-1) int[u^n(u^2 + 1)]/ (u^2 + 1) (u^2 +1) cancels out. so youre left with int(u^n)du = u^n+1/n+1...
  2. asd

    Mathematics: Post your doubts here!

    Well, For the stats question: They say there's 600 feathers, with 63 less than 6 cm, 155 more than 12 cm. so for P(X<6)= 63/600=0.105 and for P(X>12)= 155/600=0.258 (by checking from the normal distribution table you'd see theres no 0.105 or 0.258! so you gotta subtract them from 1)...
  3. asd

    Mathematics: Post your doubts here!

    Thanks! and No problem bro. :)
  4. asd

    Mathematics: Post your doubts here!

    Gradient = dy/dx = PN/TN= tanx = 1/2(PN)(TN) For part (i): Rearrange PN/TN = tanx to give TN= PN/tanx Substitute this into Area of the triangle (1/2 PN*TN) which gives 1/2* (PN)*(PN/tanx) Note that PN= y. So it goes down to 1/2. y^2. cotx Now for part (ii): Separate the variables and...
  5. asd

    Mathematics: Post your doubts here!

    There's no Q6 part (iii) in may june 2012 P61..
  6. asd

    Mathematics: Post your doubts here!

    LOOL. PLEEASSEE DUDE. I swear I think its easy! :P I find mechanics harder seriously.
  7. asd

    Mathematics: Post your doubts here!

    Haha, sure why not! :3
  8. asd

    Mathematics: Post your doubts here!

    yeah, is it not?
  9. asd

    Mathematics: Post your doubts here!

    I'm so happy I already gave mechanics exam last year. Stats FTW. it's so easy. :')
  10. asd

    Mathematics: Post your doubts here!

    Rate of flow of the liquid into the tank: 80 Rate of flow of the liquid out of the tank: kV Rate of change of liquid in the tank= 80-kV dV/dt= 80 -kV dV/(80-kV) = dt = ∫ dV/(80-kV) = ∫ dt = -1/k ln(80-kV) = t = ln(80-kV) = -kt = 80-kV= e^(-kt) + c (N.B: c = o) = -kV= -80+ e^(-kt) = V=...
  11. asd

    Mathematics: Post your doubts here!

    Im guessing that's supposed to be a " . " in place of " x "? 'cause their cross product is definitely not a 0. Well, thanks anyways!
  12. asd

    Mathematics: Post your doubts here!

    I hope its clear enough that you can read it :p My webcam sucks and my cell wont connect to my laptop! :///
  13. asd

    Mathematics: Post your doubts here!

    Asking you why my method is wrong
  14. asd

    Mathematics: Post your doubts here!

    But for the same question daredevil asked, why doesn't my method work? Here's the method sumeru: Since they ask for the shortest distance from the point p to the line that lies ON the plane, so we can use the normal vector of the plane as the directional vector for the line equation PX, where X...
  15. asd

    Mathematics: Post your doubts here!

    http://www.netcomuk.co.uk/~jenolive/vect18e.html Here's a detailed method and I'm getting sqrt[5] using this. I did method 2.
  16. asd

    Mathematics: Post your doubts here!

    Oct Nov 2007, Q7, part (ii) Why are we supposed to use the radian mode instead of degree mode? http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w07_qp_3.pdf
  17. asd

    Mathematics: Post your doubts here!

    Dude, you're a genius. You must be taking Further Maths Lel.
  18. asd

    Mathematics: Post your doubts here!

    Oct Nov 2007, Q7, part (ii) Why are we supposed to use the radian mode instead of degree mode? http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w07_qp_3.pdf
  19. asd

    Mathematics: Post your doubts here!

    So basically, what I did is correct as well? cause its just the reverse of what you did.
  20. asd

    Mathematics: Post your doubts here!

    Could you do the "show" part in the same question as well? Well, Ik that |z-2i| = 4 is gonna go to: a^2 + b^2 -4b +4 = 16 a^2 + b^2 -4b -12 = 0 which is same as zz* - 2iz* + 2iz -12= o. But is this enough to show what theyre asking for?
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