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Mathematics: Post your doubts here!

4x^2- 7x-1/ [x+1][2x-3] = A+ {B/[x+1]}+{C/[2x-3]} Now multiply x+1 on the R.h.s which will give u 4x^2-7x-1/[2x-3] then, substitue x=-1 to get B. Repeat the same for C, but thn now multiply the R.h.s with [2x-3] so here x= 3/2 to find A, substitute any num, say for example x= 0 on either sides...
- Riya
- Post #5,074
- Oct 29, 2012
- Forum: A-Levels
R
Mathematics: Post your doubts here!

Can anyone help me wid qstn no 10, pls!?? http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w11_qp_33.pdf
- Riya
- Post #5,041
- Oct 29, 2012
- Forum: A-Levels
R
Holaaaa!! xD

:)
- Riya
- Post #5
- Oct 28, 2012
- Forum: Welcome Lounge
R
Holaaaa!! xD

Riya here! :D
- Riya
- Thread
- Oct 28, 2012
- Replies: 10
- Forum: Welcome Lounge

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