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  1. D

    1. 0.1112. 0.07,0.1283. 34.2,0.9204. 75,mean=213 sd=48.7 5. 0.0763,0.8726...

    1. 0.1112. 0.07,0.1283. 34.2,0.9204. 75,mean=213 sd=48.7 5. 0.0763,0.8726. 1663200,30240,141127,107.0.5,pd table,1/6 not equal to 1/5, 1/6 not equal to 0 Cnfrm me answers
  2. D

    How was maths p62?

    inclusive means we dnt have to aproximate n its in aproximation that we add or minus 0.5 rite inclusive means including 38 n 41 tht means rite away p less than exact 38 subracted from p less than exact 41
  3. D

    How was maths p62?

    i do have all the answers noted
  4. D

    how was M1 42

    well but then the formula for power is differebt ib tht case its P=Fcos0 come on hows it possible to ignore he weight component
  5. D

    how was M1 42

    no mine was not this hehe
  6. D

    how was M1 42

    h how cum? 25.6?
  7. D

    how was M1 42

    well for the third one yea it was for 2 marks i simply applied distance formula v2=u2+2as cs we had distance 216 final velocity 0 a=-0.72 and calculated v
  8. D

    how was M1 42

    well i remember the distance OA was 216m for b part it was like -0.72m/s2 n for third part iam confused
  9. D

    how was M1 42

    yup i got the same and wht abt last ques last part?
  10. D

    how was M1 42

  11. D

    how was M1 42

    n wht abt last ques last part the one for initial speed?
  12. D

    how was M1 42

    n was q 4 answer 39N n diection 22.6'AC from x direction ?
  13. D

    how was M1 42

    well iam not repearing i completed my maths in 3 months n have given as paper and as far as my little experience works its impossble to ignore x component of weight cs it was a slope the rest is with the mark scheme
  14. D

    how was M1 42

    w well i dont get it hows this possible like u mean when we were calculating f=ma for driving force we only had to subract 1000N resistance from driving force n equal it to ma?we dont have to subract the x component of weight? n then when we get df then simply power=force x velocity to get velocit?
  15. D

    how was M1 42

    well u r talking abt mayjune 2012 paper? i ignored the weight x component n took friction directly n i dont get it u mean that u had not calculated x component of weight separately and got ques rite?
  16. D

    how was M1 42

    if u c an get me all values i can tell the answer b calculations
  17. D

    how was M1 42

    n my q 6 is wrong well i didnt add up the x component of weight so how many marks i wld loose? in later in part two ?
  18. D

    how was M1 42

    well can u cnfrm me abt all my answers my Q6 is wrong wht abt the else ? hmm n for coefficient pasrt from rite we had angle 30 in part a hmm then we calculated the forward component of weight we had the acceleration so it was forward-friction=mxa then we got friction then divide by normal...
  19. D

    how was M1 42

    IT was not 0.4 it was 4 at bottom man
  20. D

    how was M1 42

    WELL I USED IT CS OF EXAM TRICK AS USUALY PARTS OF QUES ARE LINKED SO I LOOKED AT WE HAVE THE DISTANCE THE ACCELERATION THE FINAL VELOCITY SO Y NOT USE A FORMULA ALSO THAT SPEED WAS NON CONSTANT NOT THE ACCELERATION
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