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4040 Statistics 2011 and Paper discussion after 24 hours

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tahatehseen said:
Any one out there?
There was a question like this:
If there are lets say 20 objects. And they have a mean of 240g and Standard Deviation of 15g. They are packaged into boxes of mass 50 g each.. What is the mean and standard deiation of the packaged goods?
mean....290
s.d ..same...15
 
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usman.1995 said:
tahatehseen said:
Any one out there?
There was a question like this:
If there are lets say 20 objects. And they have a mean of 240g and Standard Deviation of 15g. They are packaged into boxes of mass 50 g each.. What is the mean and standard deiation of the packaged goods?
mean....290
s.d ..same...15

So in the stats paper the packaged food items question.... Wasnt it similar?
 
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usman.1995 said:
Thanks Man! You really eased things out :p BTW SalmanPakRocks wrote the answer (referring to the question above)
Mean: 40
Standard Deviation: 0

Is is correct?
 
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SD cant b zero...it had to b same that in previous part...
well answer in exam we
MEAN=450.5 grams upto 1 d.p
S>D =2.0 grams upto 1 dp
part b...mean = 630.5 g
SD =same ...2.0
 
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Alright, qs 2 (a) (iii) , answer was Quota, since it asked, first 3 boys and first 3 girls that enter the room. Answer to qs 6 (ii) was 5/6 + (1/6 x 3/4) = 23/24 . Answer to qs 6 (iii) was 23/24 x 23/24 x 23/24 x (1/6 x 1/4) = 0.037.
 
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perfect1 said:
Alright, qs 2 (a) (iii) , answer was Quota, since it asked, first 3 boys and first 3 girls that enter the room. Answer to qs 6 (ii) was 5/6 + (1/6 x 3/4) = 23/24 . Answer to qs 6 (iii) was 23/24 x 23/24 x 23/24 x (1/6 x 1/4) = 0.037.

Why are you multiplying 23/24 three times???
The question just asked the probability "XYZ" won the prize the second time. Which is equal to just
(23/24)*(1/24)
 
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SalmanPakRocks said:
fahadferozali said:
SALMAN, Most of your answers are certainly WRONG. SERIOUSLY!!!
How can u be so sure about it ? DO u the examiner report and please stick to the topic and discuss the paper other than judging people!! It seems that ur so over confident that u think u'll be getting distintion?
Dude chill! :beer: It was a very tough paper and i certainly know that i might have got my answers incorrect. Lets just see which of our answers are wrong!
So! What was the answer of Question 1? The one about mean median and interquartile range?
 
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waztaz123 said:
perfect1 said:
Alright, qs 2 (a) (iii) , answer was Quota, since it asked, first 3 boys and first 3 girls that enter the room. Answer to qs 6 (ii) was 5/6 + (1/6 x 3/4) = 23/24 . Answer to qs 6 (iii) was 23/24 x 23/24 x 23/24 x (1/6 x 1/4) = 0.037.

Why are you multiplying 23/24 three times???
The question just asked the probability "XYZ" won the prize the second time. Which is equal to just
(23/24)*(1/24)
Xyz won the exam in HIS second term! That is when ABC starts, ABC loses his first term, XYZ loses his first term, ABC loses his second term, and then XYZ wins his second term, and then the game stops. So it would be 23/24*23/24*23/24*1/6*1/4
It should be kept in mind that the game would end when someone wins
 
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SalmanPakRocks said:
I m sorry if I was rude, but seriously. I m already so tensed and that person is making my tension go double! anyways I aknowledge that I lost more than 26 marks in Paper 1 to be exact (actually I have deducted the marks i lost in section 1 where as I have also deducted 3 marks from each question of section 2).
Man it was VERY difficult! BTW do you remember your answer to 1st question last part?
 
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