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So? No questions?
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well im not sure bout this but according to me its Ahttp://onlineexamhelp.com/wp-content/uploads/2014/08/9700_s14_qp_12.pdf
Can any1 help me with question number 18 of this paper
B. This shows highest increase of saturation per change in partial pressure of oxygen.View attachment 51958
Please Help. Thanks!!
A2 student here . I use CIE book; amazing compilation!Hey guys, anyone from A2? There's exactly 25 days left till biology paper 5. How are you guys revising? I'm going over the syallbus for the third time after that just going to do pastpapers
Be more specific!Hi guys, can anyone tell me during phloem loading, hydrogen ion is passed from the companion cell into the cell wall or cytoplasm of the plant cell? My course book stated there it passes into the cell wall, causing a high concentration of it in apoplast. But my lecturer told me that it was pumped into the cytoplasm of it and the older version of coursebook said so. Thank you
Follow the coursebook. H+ ions move into the cell wall.Hi guys, can anyone tell me during phloem loading, hydrogen ion is passed from the companion cell into the cell wall or cytoplasm of the plant cell? My course book stated there it passes into the cell wall, causing a high concentration of it in apoplast. But my lecturer told me that it was pumped into the cytoplasm of it and the older version of coursebook said so. Thank you
Also the revision guide for the cie book is excellentA2 student here . I use CIE book; amazing compilation!
Thanku for replying, but i dont understand how the sample number is 12 in Q1c(i) and y multiply 2.5 with 112 in Q12Well P52 Q1b(i), they are asking for the value of t for INTERNODE LENGTH , X1 and X2 are the mean values of both the types of leaves. In the table 1.1, the values are written in the form of Mean +- Standard deviation, therefore 23-19, S2 and N2 are the standard deviation and the number of samples and thus 3^2 / 30, and therefore the final answer 8.9.
Nov 2010 P53 Q1c(i), the formula is for the Standard error, simply you will have to divide by the square root of the number of samples, therefore, you will divide by square root of 12, and then round the answer of 1.15 to 1
Nov 2011 P53 Q2b(ii) , Chi-square test, you need the total number of samples first, which will simply be 112 (40+72) or from table 2.1 add all the values of Cross1, as offspring with tail is recessive lets say, 0.25 * 112 = 28, and therefore 112-28= 84. Just put these values in the formula given and add both these results at the end to get 6.86(after rounding to 2dp)
Is it the exdexel one?For those in AS GET THE REVISION GUIDE. it will help you SO much. I got if for free on an app called scribd but I think now you have to pay for it, otherwise I think it is available in stores. With hard work, past papers and that your bound to get a high A. Do yourself a favour and get it
Can anyone PLEASE post MJ 13 Examiner report here? I NEED IT! It's very important!
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