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CO2 binds with haemoglobin at terminal -NH2 groups, forming carbaminohaemoglobin. Whereas oxygen binds with haem groups containing Fe+2. CO also binds with haem group, as you know that it's binding reduces the affinity of haemoglobin for oxygen (thus an indication that CO and O2 have similar binding sites).Can someone please explain this question? Answer is C
View attachment 60214
Remember the oocyte doesnot complete its division uptil fertilisationView attachment 60211
mp6 not clear what does it mean meiosis complete
Because the axon membrane has more protein channels for potassium than for sodium therefore it's natural for some potassium ions to diffuse out faster than sodium diffuses in. But at the same time there are many negatively charged molecules inside the cells of the axon that attract K+. This REDUCES the chance of K+ ions diffusing outdescribe how resting potential is maintained across the axon membrane
12. idea of leaking k ion is responsible for resting potential
13.electrochemical gradient
what does this MS points mean i thougtt that resting potential was caused by na-k pump puming 2k ion in while pumping 3 na ions out so this unfair pumping resulting in resting potential
i think because suppose carbohydrate represents 60% of mass of a seed but when outer layer is removed , the carbohydrate will represent even a higher percentage of 80% of seed massWhy does the carbohydrate content of a seed increased when the outer layer of the seed is removed? Is it because the starch cam no longer be hydrolysed into maltose and glucose as the aluerone layer of the seed contains amylase which is activated by GA in the embryo which is also removed??? And where is fibre present in a seed?
Is it C? :3View attachment 60240
can anyone please explain this? how changing gases can affect diffusion or active transport rate?
yahIs it C? :3
Oxygen is required for aerobic respiration. Aerobic respiration results in formation of ATP which is utilised for active transport of substances. You can see that the graph of 3 carbon sugar remains unchanged that means that the transport of this sugar is not active rather passive. Whereas 6 carbon sugar is not transported in absence of oxygen (graph 2), which shows that its transport is active.
thanksOxygen is required for aerobic respiration. Aerobic respiration results in formation of ATP which is utilised for active transport of substances. You can see that the graph of 3 carbon sugar remains unchanged that means that the transport of this sugar is not active rather passive. Whereas 6 carbon sugar is not transported in absence of oxygen (graph 2), which shows that its transport is active.
Therefore C.
I think this is how it is.Guys plz help
Q25)A
Q19)C
Q23)A
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