A level Statistics doubt??Post your doubts here!

[Anika Raisa]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_63.pdf
please help me with 6(iii), permutation, stuck with it for an hr already still cant seem to solve it

Mrs Brown = 3 *C *1 Mrs Lin = 10 *C*1 Student = 5*C*1

Prob= (3*10*5*11P9)/(4.36*10^6)
Ans = 0.0687


NB: I m nt sure abt ans

Btwn ppl in this thread pls help each other …

 

[Anika Raisa]

mynameisjh u may find this well xplained in prev posts here ... i remember a lot of ppl hvin prob wid dis last session ... BOL!

 

[mynameisjh]

mynameisjh u may find this well xplained in prev posts here ... i remember a lot of ppl hvin prob wid dis last session ... BOL!

thank you very much!!

 

[Anika Raisa]

mention not jst feels gud 2 help

thank you very much!!

 

[Anika Raisa]

AliyaP said: ↑

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_31.pdf

question 9..PLEASSEEE HELP!!! ​

post#541
Tanweer Joomunbaccus said: ↑

Can u guys please help me in June 2012 paper 62 no-3 ?​

post#542

mynameisjh Btwn pls mind helping(if u can) AliyaP n Tanweer Joomunbaccus .... Thank u.

(PS. i wud hv helped bt i am done wid Alevels n i had created this thread for i loved S1 n believed you ppl will continue helping each other like my Xtremepapers brothers and sisters did back during my time)...

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s05_qp_6.pdf


How to do Question 6 (ii) please someone help me !

 

[Sameer Farooq]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_6.pdf


How to do Question 6 (ii) please someone help me !

Here you go!!

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_61.pdf

Q5 Full can someone explain please detailed ! thanks ^_^

 

[Rohan O]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_61.pdf

Q5 Full can someone explain please detailed ! thanks ^_^

Ask me if you don't get anything..

 

[Fahm Deen]

How to calculate the class width and midpoint for finding the mean?
May/June 11 p-61 no.6(iv).
Shouldn't the midpoint be 50 but it is given as 50.5.can someone please explain asap!!

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_61.pdf


Q3 (ii) and Q5a(ii) Please explain them

 

[Harsh Poddar]

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[Rohan O]

How to calculate the class width and midpoint for finding the mean?
May/June 11 p-61 no.6(iv).
Shouldn't the midpoint be 50 but it is given as 50.5.can someone please explain asap!!

See first of all you should realize that there is minumum 1 person in the school or it isn't a school anyway. If this idea isn't supportive then,
You can see that the next bar that is <= 100 means that's the next boundary starts from 101-150 hence the first boundary starts from 1-100 so the midpoint is 1+100/2= 50.5

 

[Rohan O]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_61.pdf


Q3 (ii) and Q5a(ii) Please explain them

And for the permutations and combinations question
See the 4 digit number needs to be between 5000-6000 so the first number needs to 5
The next three numbers can be repeated that means the 5 can come again along with the other 5 number so 1 x 6 x 6 x 6 = 216(Ans)

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_63.pdf

Q7 (ii)

 

[Rohan O]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_63.pdf

Q7 (ii)

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_61.pdf

Q2 , Q3(ii) , Q5(i), Q7(i) and Q6(iv) and (v)

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_61.pdf

Q2 , Q3(ii) , Q5(i), Q7(i) and Q6(iv) and (v)

for 5i it will be 1- (less than two choose B) so

One Chooses B = R'B'A + R'A'B + A'B'R (where ' means probability that they did not choose B)
Zero Chooses B = R'B'A'

1-(One Chooses B)-(Zero Chooses B) should give you the answer.

 

[Princess Raven]

Can anyone solve part ii why did they time it by 2?

 

[Fahm Deen]

Oct/nov 2012 paper-63 no.6(c).
Can anyone give a good explanation.