• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

A2 Mechanics (maths p5)

Messages
111
Reaction score
63
Points
38
ok differnt person have differrent thoughts!!! btw i dropped stats bcos i find it boring n it wont benefit in my engineerin course in university:)
 
Messages
111
Reaction score
63
Points
38
Well, I love everything related to Mathematics. My life won't be complicated - I'll seriously enjoy my life because of my enthusiasm in Maths.
well i love maths too!!! that doesnt mean we have to do evrything related to maths!! like i wanted to do Further mathematics this year but couldnt find a tutor!! n Further mathematics is wayy farr advance compared to our maths:rolleyes:
 
Messages
282
Reaction score
55
Points
38
Total energy at O = K.E.=0.5(0.4)(2^2)=0.8 J

Total energy at extension x:
E.P.E.(elastic potential energy)=0.5(24/3)(x^2)=4(x^2) J
G.P.E.(gravitational potential energy)=0.4(10)(-(3+x))= -12-4x J
K.E.=0.5(0.4)(v^2)=0.2(v^2) J

TOTAL ENERGY: 4(x^2) + (-12-4x) + 0.2(v^2).

Conservation of energy: total energy constant.

Therefore 4(x^2) + (-12-4x) + 0.2(v^2) = 0.8.

simplify, you will get answer.
 
Messages
438
Reaction score
106
Points
53
Total energy at O = K.E.=0.5(0.4)(2^2)=0.8 J

Total energy at extension x:
E.P.E.(elastic potential energy)=0.5(24/3)(x^2)=4(x^2) J
G.P.E.(gravitational potential energy)=0.4(10)(-(3+x))= -12-4x J
K.E.=0.5(0.4)(v^2)=0.2(v^2) J

TOTAL ENERGY: 4(x^2) + (-12-4x) + 0.2(v^2).

Conservation of energy: total energy constant.

Therefore 4(x^2) + (-12-4x) + 0.2(v^2) = 0.8.

simplify, you will get answer.
thanks
 
Top