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A2 Physics | Post your doubts here

smzimran

smzimran

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XPFMember said:
Doesnt this one (below) shows diff charging and discharging time?

​
Click to expand...
I will get back to that capacitor question wait a little, i will have to revise i believe....

In the mean time,
Q7 (b)
You assumed thar as resistance increases, power dissipation increases, but you missed that when resistance increases, current decreases!
Because P = I^2 * R
factor of I is square times while that of resistance is just to the power 1
that is why although resistance increases, the SQUARE of the decrease in current not only cancels that effect but increases decreases power dissipation
that is why damping is reduced!

Q7 (c)(iii)
http://www.xtremepapers.com/community/threads/physics-post-your-doubts-here.9860/page-73
post # 1446
 
smzimran

smzimran

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smzimran said:
Thnx, missed that point,
J07,
Q4(c)(ii)
Something like this, sorry its free hand drawing :D
Click to expand...
XPFMember said:
but then doesn't this change the time for charging and discharging...shudn't we keep it the same..?
i'm not sure..just asking..cuz m confused...
Click to expand...
smzimran said:
It should'nt because the capacitance is the same.
Click to expand...
XPFMember said:
​
7239

Doesnt this one (below) shows diff charging and discharging time?

free-png.7236
​
Click to expand...
I got this one!
The point is that the discharging time is equal to time constant which is = CR
So, if either R or C increases, time constant increases and thus discharging time will increase!
:)
 
XPFMember

XPFMember

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USMAN ALI (MANI) said:
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s05_qp_4.pdf

q5b) a detailed explanation plz that how will be the graph and whY ix the graph shaped lyk that??


q6b) all partx including bi, bii, biii,

here again m confused that hoW wil grapHx frmed and what phase angle diff.?????

explain here that why graphx are forming lyk that??:oops::ROFLMAO:(n):eek::confused::(:coffee::notworthy::sick::sleep::X3:


plx guys help me through this
m posting it thrd time :cry::cry:
Click to expand...
assalamoalaikum wr wb!

i already replied....you probably missed that out..

http://www.xtremepapers.com/communi...s-thread-no-as-posts.13317/page-4#post-199135
 
H

hassam

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http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf
q6 b ii
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf
q8 b ii
in this question....for any reaction to be feasible.....it must be forming more stable products........so ms says b.e of reactant is smaller than sum of B.E OF PRODUCTS.i am cnfused in this why we are taking sum of B.E of products .....why not saying B.E of parent nucleus is less then B.E of each of the product nucleus
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf
q4 d ii why gradient is increased..
what i think is that every value of energy for a particular x value will get doubled......so why then gradient increased
 
smzimran

smzimran

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USMAN ALI (MANI) said:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_4.pdf

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_ms_4.pdf

q6 i,2,3 what ix the direction how ar they ?? can ANy one giVe a little explanation??

the questions are simple bt m not able to take the rite concept
Click to expand...
AoA,
(i) and (ii)You know the force is towards Y --->
and current is going out of the paper
Use fleming's left hand rule to find the direction of magnetic field
;)
 
leadingguy

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smzimran said:
AoA,
(i) and (ii)You know the force is towards Y --->
and current is going out of the paper
Use fleming's left hand rule to find the direction of magnetic field
;)
Click to expand...


soRRy bt still m un able to get u
now lets have a look to mY story:D


what I am thinking is that using right hand grip rule we can see that in both wires current is upward and field is around in circular rings????


now if both fields are circular than the wires repel putting an equal and opposite force on each other.

so what does the question asks???????????? I am unable to gt the questin yet :eek:

itx tooooooooo diplomatic :D
 
smzimran

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USMAN ALI (MANI) said:
soRRy bt still m un able to get u
now lets have a look to mY story:D


what I am thinking is that using right hand grip rule we can see that in both wires current is upward and field is around in circular rings????


now if both fields are circular than the wires repel putting an equal and opposite force on each other.

so what does the question asks???????????? I am unable to gt the questin yet :eek:

itx tooooooooo diplomatic :D
Click to expand...
p.m me
 
leadingguy

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smzimran said:
AoA,
(i) and (ii)You know the force is towards Y --->
and current is going out of the paper
Use fleming's left hand rule to find the direction of magnetic field
;)
Click to expand...


why and why is the force towardx Y????? can u explain this point in detail????
it will be good if a sketch is showed plx
 
smzimran

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USMAN ALI (MANI) said:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_4.pdf

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_ms_4.pdf


qstn 1bii)

using reaction force = Fcent. + weight
mrw^2 + 5.0 = reaction force (upwards)

now what is the working, how is the working for reaction force in m.s

(L – 13) × 5/1.8 reaction force?????????? whats this??? how we arrived to this??
Click to expand...
AoA,
We know that F = ke
k = F / e
Figure 1.1 shows that an extension of (14.8 - 13.0) = 1.8 is produced by a force of 5N (weight)
So,
k = 5 / 1.8
k = 2.78

For an extension (L - 13.0),
F = ke
F = 2.78 (L - 13)
This is the force in the cord or the normal reaction force
using reaction force = Fcent. + weight
2.78 (L - 13) = mrw^2 + 5
2.78 (L – 13) = 5/9.8 × L × 10^-2 × (8.7)^2
Solve to get
L = 17.2 cm
:)
 
smzimran

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doc.ahmed

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I am not sure if u guys are in a way of studying like this but i find these easy to learn in the following hence providing you all with a way too learn Mobile Circuit.... Hope it helps..

Meri - microfone
Ami Foran - a.f amplifie
Ati - ADC
pitti - Parralell to Digital:p
marti - modulator-ossilator
aur - amplifier :D
sunati - switch
aesay - aerial

Hope it help... Will keep on posting ........... ;)
 
XPFMember

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doc.ahmed said:
I am not sure if u guys are in a way of studying like this but i find these easy to learn in the following hence providing you all with a way too learn Mobile Circuit.... Hope it helps..

Meri - microfone
Ami Foran - a.f amplifie
Ati - ADC
pitti - Parralell to Digital:p
marti - modulator-ossilator
aur - amplifier :D
sunati - switch
aesay - aerial

Hope it help... Will keep on posting ........... ;)
Click to expand...
AOA
JazakAllah khairen(y)
 
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