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look at my previous answer again, I edited it????
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look at my previous answer again, I edited it????
work done= area of the triangle
1/2 * base * height
work done is P*delta volume
so-----> 1/2* 25*10^8* ((2*10^-4)-(8*10^-4)) {as the arrow is going from R to P}
===> -840J
In an earlier question, it asked the total energy change in PQRP which is zero. So, the sum of the third column should be zero. Since we already know that the first two are -360and +720,????
base is 25*10^5...isnt it?work done= area of the triangle
1/2 * base * height
work done is P*delta volume
so-----> 1/2* 25*10^8* ((2*10^-4)-(8*10^-4)) {as the arrow is going from R to P}
===> -840J
ohh sorrry its 28*10^5base is 25*10^5...isnt it?
thats quite an over-exaggeration dont you think? Most of my doubts were answered over here... Lots of people helped me. I still have alot of unanswered doubts.@histephenson007 and SkyPilotage! How the hell did you guys prepare for physics. You guys know answers to everything!
true, thats the correct way to do it.GOT IT!!!!!!!!!!
In an earlier question, it asked the total energy change in PQRP which is zero. So, the sum of the third column should be zero. Since we already know that the first two are -360and +720,
-360+720+ x = 0
So, x = -360
Then
u = q + w
-360 = 480 + x
so, x = -360 - 480 = -840
No,i am not comfortable with the third portion and is it important to learn the range of radio frequencies .
Yes, I did some of them!aoa wr wb! for applications, did you ppl practice questions from paper 6?
Hi everyone, I'm new here
Could someone please help me with these questions:
Q3 b) (iii) - I don't understand why the increase in internal energy is ∆U = 4.05 × 10^4 – 3050 = 37500 J . Because heat enters the system, so it makes sense that it is positive, but why is the work done on the system negative? I thought that work done by the system is negative.
Q6 c) (ii) I don't understand how to sketch that graph
yes i did few days back..only medical and communication options.aoa wr wb! for applications, did you ppl practice questions from paper 6?
i am not comfortable with the third portion and is it important to learn the range of radio frequencies .
my advice to you, please do memorize at least frequencies. wavelengths can be found by v = lambda x frequencyNo,
Just remember the trend which have higher frequencies and which have lower.
you mean paper 5? I didnt even look at it -_- .. do we have to?Yes, I did some of them!
They are mostly questions that have been almost repeated in the late years
That its the network that connect telephones together.]How we should study PSTN
i meant paper 6...before 2007 there was no section B in paper 4 and instead there was a paper 6...my advice to you, please do memorize at least frequencies. wavelengths can be found by v = lambda x frequency
"(l) Candidates should be able to recall the frequencies and wavelengths used in different channels of communication. "
you mean paper 5? I didnt even look at it -_- .. do we have to?
That its the network that connect telephones together.
You should know about the trunk exchange and the international gateway exchange.
Thats basically it.
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