Additional Mathematics (0606) Doubt

[XxChampXx]

See the question said that TWO teams have to be choosen, so think of a two teams as one conplete event(or outcome) ,and a single team as half of an outcome,and if u know the basic counting principle it says that if two tasks are to occur in succesive than u MULTIPLY their odds, and by this the first part is 14C8 and second is 8C4*6C4

I did 8C4*6C4*2 because there were two teams and they did not specify which team has a boy or a girl. What did you get for the secirity code questions?

 

[The_Boss]

I did 8C4*6C4*2 because there were two teams and they did not specify which team has a boy or a girl. What did you get for the secirity code questions?

I am pretty sure that you dont need to multiply by 2 as the question was based on COMBINATION not permutation where order doesnt matter, so it didnt matter which team was selected first!

 

[The_Boss]

I did 8C4*6C4*2 because there were two teams and they did not specify which team has a boy or a girl. What did you get for the secirity code questions?

Anyway how was ur paper?

 

[XxChampXx]

Anyway how was ur paper?

I was ok. The grade thresholds are scaring me. What did you get for the permutations questions about the security code?

 

[The_Boss]

I was ok. The grade thresholds are scaring me. What did you get for the permutations questions about the security code?

20160, 2160,540

 

[XxChampXx]

20160, 2160,540

I got 20160, 2160, but my third part was 5040

 

[XxChampXx]

20160, 2160,540

And for the trigonometry second part did you have to do tan^-1(3) to get 71.6?

 

[The_Boss]

Ummm

And for the trigonometry second part did you have to do tan^-1(3) to get 71.6?

Ummmm...yeah. U mean the cot and cosec question, right?

 

[XxChampXx]

Ummm

Ummmm...yeah. U mean the cot and cosec question, right?

Yeah I thought I messed that up. Did you also get tan(x)=-0.5?

 

[XxChampXx]

Ummm

Ummmm...yeah. U mean the cot and cosec question, right?

thnkx alot sir! thank god i did it correctly. i was too much worries about it.

Were your answers 71.6, 251.6, 153.4 and 333.4 for the trigonometry second question?

 

[mathg123]

See the question said that TWO teams have to be choosen, so think of a two teams as one conplete event(or outcome) ,and a single team as half of an outcome,and if u know the basic counting principle it says that if two tasks are to occur in succesive than u MULTIPLY their odds, and by this the first part is 14C8 and second is 8C4*6C4

Are you sure that the first part answer for the two teams question was just 14C8, because even if you select 8 members, they can be rearranged into different teams right?

 

[XxChampXx]

Are you sure that the first part answer for the two teams question was just 14C8, because even if you select 8 members, they can be rearranged into different teams right?

So what do you think the answer is?

 

[mathg123]

I dont know I put 14C8, but then I realised it might be wrong after the exam. What did you put

 

[XxChampXx]

I dont know I put 14C8, but then I realised it might be wrong after the exam. What did you put

Same 14C8

 

[XxChampXx]

I dont know I put 14C8, but then I realised it might be wrong after the exam. What did you put

What did you get for the trigonometry question 2? Were your values 71.6, 251.6, 153.4 and 333.4?

 

[mathg123]

yeah I got those answers I think

 

[XxChampXx]

yeah I got those answers I think

For the security code thing third part what did you get(the one where two symbols were together)?

 

[mathg123]

For the security code thing third part what did you get(the one where two symbols were together)?

3600

 

[XxChampXx]

3600

Many people in my class got that. How?

 

[mathg123]

there are 2 ways to arrange the symbols among themselves, 6P4 ways to arrange the remaining 4 digits/letters or both and there are 5 cases in which the symbols can be next to each other. hence totally it is 5 * 6P4 * 2

What did most of the people in your class put for the 14C8 one?