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jesus abbu u think thats right i doont think so see they didnt tell us to react with conc kmn04 there was no space they only told us that alkene is present thus they showed us it reacted with kmn04 im goin crazzy here lol
so how many marks 9 right
wat abt cis trans
yes i want them break me more jesusss
i love u abby
but mine little different i named them cis e and z isomerism
Ummm.. Excuse me?
What sort of alkanes have a pi bond and a sigma bond. And what sort of chemistry exists where a compound has JUST a pi-bond.
This isn't correct. Although, from what I recall, the question was how can butane be produced, but if you were to produce Bromine in an FRSR mechanism, it'll be in termination.
Br* + Br* -> Br2 (where * shows a radical)
CH3CH2* + CH3CH2* -> C4H10 was what I, and everyone else I've asked answered.
What??
The compound did not contain a Carbonyl group!! Carbonyl group was formed after reacting it with hot KMnO4 and it tested NEGATIVE with Tollens reagent so THAT was a Ketone, not the initial, starting compound. Besides, C6H12 can never be a carbonyl anyway -_-
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