AS Biology help!!

[Ding Ding]

Can somebody help me to solve this question?
A square metre of grassland receives about 1047000 kJ of solar light energy each year.
The table shows what happens to this energy.
used in evaporation of water 523500kJ
transmitted to the ground 335000kJ
reflected by the leaves 165000kJ
used for growth 21500kJ
used for other life processes 1500kJ
respiratory heat losses 500kJ
How much energy is used by the grass in photosynthesis?
A 2000kJ B 19500kJ C 21500kJ D 23 500kJ

 

[Farhan96]

Can somebody help me to solve this question?
A square metre of grassland receives about 1047000 kJ of solar light energy each year.
The table shows what happens to this energy.
used in evaporation of water 523500kJ
transmitted to the ground 335000kJ
reflected by the leaves 165000kJ
used for growth 21500kJ
used for other life processes 1500kJ
respiratory heat losses 500kJ
How much energy is used by the grass in photosynthesis?
A 2000kJ B 19500kJ C 21500kJ D 23 500kJ

The answer would be D

 

[Vikings]

Can somebody help me to solve this question?
A square metre of grassland receives about 1047000 kJ of solar light energy each year.
The table shows what happens to this energy.
used in evaporation of water 523500kJ
transmitted to the ground 335000kJ
reflected by the leaves 165000kJ
used for growth 21500kJ
used for other life processes 1500kJ
respiratory heat losses 500kJ
How much energy is used by the grass in photosynthesis?
A 2000kJ B 19500kJ C 21500kJ D 23 500kJ

The answer would be C.

 

[Ding Ding]

[quot

The answer would be C.

The ans is C.
How can get the value?

 

[Silver Wing]

The answer is C
This is the energy used for growth as the plant has to photosynthesise to grow
Hope this has helped

 

[strangerss]

hey can anyone help in this question please ? It's question number 3 in bio p1 ,year maj/june 2010 . i just don't understand how the radius is supposed to be 0.125mm ! if the difference in the divisions is 0.1 shouldn't the total length of field be 10mm and the radius 5mm? can some one please help me out?

 

[french410]

hey can anyone help in this question please ? It's question number 3 in bio p1 ,year maj/june 2010 . i just don't understand how the radius is supposed to be 0.125mm ! if the difference in the divisions is 0.1 shouldn't the total length of field be 10mm and the radius 5mm? can some one please help me out?

IT MEANS THAT THE DIFFERENCE BETWEEN THE HUGE DIVISIONS IS 0.1 MM, EACH HUGE DIVISION COMPRISES OF 40 SMALLER UNITS. THE WHOLE DIAMETER IS 100 DIVISIONS, THAT MEANS 2.5 HUGE DIVISIONS. NOW E NEED TO FIND THE AREA WHICH IS (π*r*r) THEREFORE RADIUS IS 50 SMALL DIVISIONS THAT IS 1.25 HUGE DIVISIONS. EACH HUGE DIVISION BEING 0.1MM MEANS THAT 1.25 HUGE DIVISIONS ARE 0.125MM, WHICH IS EQUAL TO 125 MICROMETERS. THUS THE AREA IS π*125*125=49000MICROMETERS.

HOPE THAT HELPED!!

 

[strangerss]

Thank you so much that was extremely helpful , I had no idea what the huge divisions were for , this explains a lot. thank you once again , none of my teachers were able to solve this hehehe.

 

[french410]

Thank you so much that was extremely helpful , I had no idea what the huge divisions were for , this explains a lot. thank you once again , none of my teachers were able to solve this hehehe.

no problem anytime

 

[Areeba Shahnawaz]

easiest q ever
u v to add energy of : used for growth , for other life processes and for respiratory heat losses

 

[sweetiepie]

As http://www.xtremepapers.com/community/threads/as-biology-post-your-doubts-here.9858/
A2 http://www.xtremepapers.com/community/threads/a2-biology-post-your-doubts-here.13612/

post here your doubts