m/j/09 ==> it is obvious dat if semi-conservative replications takes place den the % of cells containing N15 will decrease and N14 will increase.june 09 / p1 / q22
june 10 / p11 / q3
so v hav to curves with a decrease in % cells containing N15...the answer can't b D bcos if the 2nd generation has 50% cells den the 3rd generation wont directly reduce to 0%...there will b sum cells atleast wid say hybrid DNA(containing both N15 and N14)...so dat means der r sum cells containing N15...thus the answer is C and not D....got it?
N i dont noe the other question...