as physics help please happy friendship day guys

[tanmaydube]

Please help me these two questions:

Q1) In a driving manual, it is suggested that, when driving at 13ms^-1(about 45 km per hour), a driver should always keep a minimum of two car-lengths between the driver's car and the one in front.
A)Suggest a scientific justification for the safety tip, making reasonable assumptions about the magnitudes of any quantities you need.
B)How would you expect the length of the 'exclusion zone' to depend on speed for speeds higher than 13ms^-1?

And the question number 2 is:

Q2) A student, standing on the platform at a railway station, notices that the first two carriages of an arriving train pass her in 2.0s, and the next two in 2.4s. The train is decelerating uniformly. Each carriage is 20 m long. When the train stops, the student is opposite the last carriage. How many carriages are there in the train?

 

[destined007]

Q1) a) justification could be that if the front cars stops suddenly, you do not crash into it. Whenever you see an obstacle, you take some time to analyse it. This is called reaction time. When you have fully analysed the situation then you apply breaks. The distance you cover after the breaks are applied is called breaking distance. The distance it will take you to stop when moving with 13ms-1 and decelerating at 15 ms-2 (lets suppose) when breaks are applied will be around 5.63 m, which is less than the length of 2 cars combined. You won't hit the front car.

b) as speed increases, length of exclusion time also increases. v^2=s/(2a)

 

[destined007]

Q2)
Tell me if i am correct.

 

[tanmaydube]

Thanks mate! You are absolutely right!

 

[hassam]

perfect soln man

 

[destined007]

You are welcome!

 

[dentaladvicetoday]

Dental Advice Today​

Dental Advice Today was created to help people take charge of their oral health by providing accurate and clear resources. We believe that knowledge leads to confidence and healthier choices. At Dental Advice Today, we bring expert insights into everyday language, making dentistry more approachable. Our goal is to support individuals in every stage of their dental journey. Visit our site today and learn how expert advice can guide you toward a brighter and healthier smile.

 

[peterfarmer]

Hi! I’m working through these physics problems and would really appreciate some help or guidance:
Q1:
(A) I need to scientifically justify the driving manual’s tip about keeping two car-lengths distance at 13 m/s. What reasonable assumptions should I make to support this?
(B) Also, how would the required safety distance (the exclusion zone) change as speed increases beyond 13 m/s?
Q2:
A student observes a uniformly decelerating train:

• The first two 20 m carriages pass her in 2.0 s.
• The next two take 2.4 s.
  She ends up opposite the last carriage when the train stops.
  How many carriages does the train have in total?

Thanks in advance for any help or explanation!

Space Waves​

 

[jasonlogan]

Q1: The 2-car-length rule gives enough distance for a driver to react and brake safely. At 13 m/s, assuming ~1.5 s reaction time and typical braking deceleration (~6 m/s²), it makes sense. At higher speeds, stopping distance increases with the square of speed, so the safe gap should increase too.
Q2: Nice observation! The train is decelerating uniformly, and the time to pass each carriage increases. You can use equations of motion to calculate the deceleration and total distance passed. Since each carriage is 20 m, and total distance = number of carriages × 20, it’s a kinematics problem. The answer is 8 carriages.

Snow Rider​

 

[thore12]

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