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12 first... since applied force is constant, the torque (F*d) will be proportional to d.... torque for 100mm is 3.. so for 150mm , it will be 4.5Nm... so we have to look for the tensions now..torque is the product of force and moment arm.. and the only force present here is the tension in the belt so 3=F*.1 F=30N
20.. was so simple yaar... find area under the curve.. ok.. draw a straight line from 0,0 to P... and use 0.5* base * height.. this wil give u 0.1 as answer.. now it is clear that the area you have found is less than the original one but double to it.. so option just little greater than 0.1 isC...
Oh, alright. Thanks.
And if it's not too much trouble, could you explain question 9 from the same paper? The one about the train.
umarashraf thnx lsn i got them all but plz help me wd Q 2 and 37
but shouldnt just da proton number increase????? why is da nucleon nmbr increasing if its beta emission?
oh GOD am such a loser
nae sory its dis ppr Q no 37
oh GOD am such a loser
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_12.pdf
ugh yes but yyyyyyyyy??? y isnt it B????? it should be 8 Li4 so y is it 7 Li 4??
lol am asking somebody else for help in odr pprs thro pm
was copying down da answers yar
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