AS Physics P1 MCQs Preparation Thread.

[xxfarhaxx]

can u plz help me in q 34 of the same paper?

find da total currnt in da circiut..V/R=I..so 9/60= 0.15 A
using ths currnt find da pd across P n Q... V=IR = 0.15* 50= 7.5v.. so and B

 

[xxfarhaxx]

time for ma doubts nw ... pls do solve them.....plsssssssssss!!!!!!!!!!
Q- 12, 25, 28, 31, 33, 34

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_ms_1.pdf

 

[USMAN Sheikh]

find da total currnt in da circiut..V/R=I..so 9/60= 0.15 A
using ths currnt find da pd across P n Q... V=IR = 0.15* 50= 7.5v.. so and B

can u help me out too pls mate

 

[xxfarhaxx]

can u help me out too pls mate

sure..bt do u wnt hlp in ths qustion...

 

[SalmanslK]

Why A?

 

[USMAN Sheikh]

sure..bt do u wnt hlp in ths qustion...

its posted on previous page in big yellow fonts

 

[USMAN Sheikh]

any one pls help needed queston no 5

 

[xxfarhaxx]

its posted on previous page in big yellow fonts

gve me 10 mis ..il solve them fr u!!

 

[USMAN Sheikh]

gve me 10 mis ..il solve them fr u!!

k thanks alot and these too 8 15 20

 

[USMAN Sheikh]

any one pls help needed queston no 5

gve me 10 mis ..il solve them fr u!!

 

[Oliveme]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_ms_1.pdf

oh right. sorry, my bad. I was looking at biology. I hope that got you somewhere because honestly I can't anymore help as it's a difficult question.

 

[DARK DRAGON]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_qp_1.pdf
Q33 answer is C plz explain

this question seems hard, can anyone explain?

 

[xxfarhaxx]

Anyone pls plss q13 25 and 26 pls pls do reply

Q 13..in ths question v consider KE to b eqaul to the components... so KE= the horizontal component, i,e 1) KE=1/2 m (v cos 45)^2 or 2) KE= 1/2 m V^2 cos 45^2....
.. at the highest point velocity = 0, tats da reason ve use the horizontal component..n not the verticle...here we will use da 2nd equations...
1/2mv^2= E.. ..therfr substitue ths in da equation where u will gt KE= E cos 45^2...
= cos 45^2= o.5. =o.5E------- ans A

fr qustn 25,,i keep gtn da ans as A..bt ms sys its D...il try figurin out n thn let u knw...

hav i made ma slf clear???

 

[trgirl]

f********ck!!!! after seeing these questions and realize that i m not able to solve thme so i felt that i will fail!!!! should i just stop studying?

 

[geek101]

this question seems hard, can anyone explain?

use the equation R = PL / A here P = resistivity
since R = V/ I
then V / I = PL / A
rearrange to make I the subject, you get I = VA / PL
now since P is the same its the same material so ignore it....
the v is now 2v and l is now 2l and since the diameter is doubled the radius is also doubled, and in area we use r^2 so the area increases by a factor of 2^2 = 4 so now its 4A
pop it into the equation = 2V x 4A / 2L = 4I

 

[xxfarhaxx]

f********ck!!!! after seeing these questions and realize that i m not able to solve thme so i felt that i will fail!!!! should i just stop studying?

tat wont hlp..knw ur theory n do all da possibl pst prps..u will b abl to do it..aftr all u cn post ur doubts or any kind of hlp u need ..tats y v ppl r thr ryt??
its neva too lts..u cn strt fresh!!!

 

[xxfarhaxx]

time for ma doubts nw ... pls do solve them.....plsssssssssss!!!!!!!!!!
Q- 12, 25, 28, 31, 33, 34

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_ms_1.pdf

sum1 do clear ma doubts!!!

 

[kinglynx]

I already did..

yeah but it didnt make sense... the numbr of neutrons on both sides is the same.. so how can u say they are not conserved

 

[USMAN Sheikh]

Q 13..in ths question v consider KE to b eqaul to the components... so KE= the horizontal component, i,e 1) KE=1/2 m (v cos 45)^2 or 2) KE= 1/2 m V^2 cos 45^2....
.. at the highest point velocity = 0, tats da reason ve use the horizontal component..n not the verticle...here we will use da 2nd equations...
1/2mv^2= E.. ..therfr substitue ths in da equation where u will gt KE= E cos 45^2...
= cos 45^2= o.5. =o.5E------- ans A

fr qustn 25,,i keep gtn da ans as A..bt ms sys its D...il try figurin out n thn let u knw...

hav i made ma slf clear???

nothing clear !

 

[USMAN Sheikh]

Any one pls help me out wit dese questions plsss
Q 13 25 26 of N09
Q8 15 20 of J10 variant 12
q5 N10 variant 11

HELP WILL BE APPRECIATED THANKS ALOT