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leosco1995 on page 41 u can find all my queries in yellow and in REd colour plsss yar help me out man 
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AS Physics P1 MCQs Preparation Thread.
- Thread starter mujtabashahnawaz
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Can somebody explain the effect of increase in diameter of a wire on extension????
Thank You
Thank You
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where can i find may/june 2002,2001 and oct/nov 2001 past papers and marking shemes pls
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http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_11.pdf
q5.
this is how i got the answer, im not sure of my way thou
Frequency: 3000 oscillations in a min, ie, 3000/60sec= 50
now Time period= 1/50= 0.02
and so for time base, as this is for one full wave, divide it by 2, 0.02/2= 0.01
Answer is B. My answer is correct but i dont know about my method.
:\
q5.
this is how i got the answer, im not sure of my way thou
Frequency: 3000 oscillations in a min, ie, 3000/60sec= 50
now Time period= 1/50= 0.02
and so for time base, as this is for one full wave, divide it by 2, 0.02/2= 0.01
Answer is B. My answer is correct but i dont know about my method.
:\
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s03_qp_1.pdf
in qs 3 the resultant is the line joining the two vectors and completing the triangle, or is the line coming from the middle of the vectors. Are both of these the resultants or not.
in qs 15, why is A the answer. The graph is decreasing so we know from a fact that air resistance increases with time so shouldnt it not be air resistance as a decreasing curve is being shown. HElp required in these questions please
in qs 3 the resultant is the line joining the two vectors and completing the triangle, or is the line coming from the middle of the vectors. Are both of these the resultants or not.
in qs 15, why is A the answer. The graph is decreasing so we know from a fact that air resistance increases with time so shouldnt it not be air resistance as a decreasing curve is being shown. HElp required in these questions please
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Thumbs UP!!! you are right!!http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf
q5.
this is how i got the answer, im not sure of my way thou
Frequency: 3000 oscillations in a min, ie, 3000/60sec= 50
now Time period= 1/50= 0.02
and so for time base, as this is for one full wave, divide it by 2, 0.02/2= 0.01
Answer is B. My answer is correct but i dont know about my method.
:\
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http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf
in qs 3 the resultant is the line joining the two vectors and completing the triangle, or is the line coming from the middle of the vectors. Are both of these the resultants or not.
in qs 15, why is A the answer. The graph is decreasing so we know from a fact that air resistance increases with time so shouldnt it not be air resistance as a decreasing curve is being shown. HElp required in these questions please
For question 3, use the paralellogram law i.e. the line coming from middle the two vectors, be careful about the angle u would use!
In Q15. When falling in air resistance, the graph of FORCE Y clearly indicates that resultant force has to be zero as the ball is reaching a constant velocity (Newton's first law).. As for FORCE X, it cannot be upthrust as upthrust in air negligible but since velocity was initially increasing, air resistance will also be increasing and when velocity is constant, so does air resistance.
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but the graph shows a decreasing gradient.
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Note that we have to calculate the POWER in this question.
Since, Power=Force X velocity
note that both the masses are in opposite direction. So basically the resultant force has to be (m1 - m2) and since W=mg
you can calculate the resultant force acting and using the velocity, the answer becomes (m1-m2)gv
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See, the thing you need to understand is that air resistance varies according to the velocity of the object.
Since initially, velocity was increasing, so did the air resistance, and when velocity became constant, so does the air resistance. Had the air resistance kept on increasing, the resultant force would not be zero.
aah...c...keep dat formula in mind while solving such Questns... n(lambda)=d.sin(theta)
now...if the no. of lines per metre are increased so the grating spacing decreases ryt? (e.g. if there r 300 lines/metre, d1=1/300 and if there are 400 lines/metre, d2=1/400....so here d2<d1...get it?)
according to the formula, n is directly proportional to d so here "d" decreases and so does "n"
and sin(theta) is inversely proportional to "d" so theta increases here...so the answer is ==>B
i guess that shud b helpful..
26) 1/8 of a cycle = 0.125
each half a wave is taking 2s to complete as 18/9 gaps = 2s
2x0.125= 0.25
18x0.25 = 4.5s
can u xplain properly ki y did u divide by 2?
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Thnx man