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AS Physics P1 MCQs Preparation Thread.

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Q 27 its D... it can either be A or D...it cant be A cz lines cant be parallel there
for 14 use Esin45..u dont have E so just use sin 45... and i dont exactly know hw 2 explain dis so sory :)
i dont really understand your explanation of Q27, can you try again?

And for 14, its fine i know how to do it now :) thanks
 

N.M

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oh yeap D.. how did u get it? I thought 2x since 0.5lambda=x.. but not right

see as you throw the ball downwards the G.P.E converts into K.E
so mgh=1/2mu^2
make u the subject
(2mgh/m)^-0.5=u
u=(2mgh)^-0.5

then take out separately an expression for v
so u said that the ball rises half the height than b4
so 1/2mv^2=mgh/2
make v the subject
you will get this after simplification
v= (gh)^-0.5

now substitute the value of v and u in to
v/u
and u will get the answer

hope its clear now
 
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can sum1 post the solution for this questn pls? :)
 

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i dont really understand your explanation of Q27, can you try again?

And for 14, its fine i know how to do it now :) thanks
u wont get anything believe me...all i know is they can never be straight lines....my theory is sort of based on logic...u shud ask sm1 else 4 explanation :)
 
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lol yea will write it here but it wont be dat clear mayb...
R=pl/A so p=RA/l
Ry*(A/4)/4l = Rx*A/l
A and l gets cancelled out both da syds so ur left wd Ry/Rx=16/1 ;)
okay tq ^^ just wonder why is there A/4?? because of volume? actually I dont really get what is meant by same volume :p haha
 
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okay tq ^^ just wonder why is there A/4?? because of volume? actually I dont really get what is meant by same volume :p haha
consider da formula V=A* l they said volume is same and its 4 tyms long...so V=A*4l...for V 2 be constant we divide A by 4 to cancel them out...umm is it clear?:oops:
 
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