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AS Physics P1 MCQs Preparation Thread.

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View attachment 12948

View attachment 12949

can u explain these?? the answers are 10.C and 13.B
For question 13, the 900N force and the force 'F' are acting in opposite directions so you'll have to equate their equations. Now the force of 900N is acting at a distance of 0.2m from the centre of the disc (consider it the pivot). So the equation for its moment of force will be = 900 x 0.2
The forces 'F' form a couple, so you'll have to take the total distance between the which is 1.2m and multiply it with 'F'. Now equating the equations you'll get:

900 x 0.2 = F x 1.2

Solve it and you'll get F = 150N :)
 
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For question 13, the 900N force and the force 'F' are acting in opposite directions so you'll have to equate their equations. Now the force of 900N is acting at a distance of 0.2m from the centre of the disc (consider it the pivot). So the equation for its moment of force will be = 900 x 0.2
The forces 'F' form a couple, so you'll have to take the total distance between the which is 1.2m and multiply it with 'F'. Now equating the equations you'll get:

900 x 0.2 = F x 1.2

Solve it and you'll get F = 150N :)
thank you ^^ really helpful
 
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Listen guys, what is conserved in a nuclear reaction and what isn't?
PLEASE HELP I"M REALLY CONFUSED :confused:
 
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