AS Physics P1 MCQs Preparation Thread.

[Monojit Saha]

5 An athlete bends down and then jumps straight up into the air. At the instant he starts his jump three forces act on him – his weight, an upthrust from the air and the contact force with the
ground. What is the correct order in increasing magnitude of these three forces? [1]
A contact force → weight → upthrust
B upthrust → contact force → weight
C upthrust → weight → contact force

D weight → upthrust → contact force ANyone?...

 

[lunafawkes]

v=f x lambda. f=8/50=0.16 Hz. v=2 x pi x 2 x 0.16. K.E.=1/2xmx(v^2).

thank you, and if you could also explain Q 25, i'd be grateful!

 

[h4rriet]

thank you, and if you could also explain Q 25, i'd be grateful!

Sure: d x sin(theta)=n x lambda. d & lambda are constants, so d/lambda=n/(sin(theta))=k. So 3/(sin45)=x/(sin90), because the highest order occurs at 90 degrees.

 

[lunafawkes]

Sure: d x sin(theta)=n x lambda. d & lambda are constants, so d/lambda=n/(sin(theta))=k. So 3/(sin45)=x/(sin90), because the highest order occurs at 90 degrees.

i understand, thanks again

 

[shazorkhaledhossain]

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w03_qp_1.pdf
I get it why it's not C and D cause the're progressive waves, but why isn't it B ? :/

 

[syed1995]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w03_qp_1.pdf
I get it why it's not C and D cause the're progressive waves, but why isn't it B ? :/

Which question dude?

 

[shazorkhaledhossain]

Which question dude?

Oh sorry, number 26

 

[hela]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf Q23 A

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf Q12 A

 

[ahmed abdulla]

????

 

[hela]

please help
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf Q23 A

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf Q12 A
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w09_qp_11.pdf Q12 B

 

[Monojit Saha]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf NUMBER 36 ..

 

[Monojit Saha]

please help
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf Q23 A

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf Q12 A
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf Q12 B

OCT NOV 12 Paper 11 number 23:
F=ke
For spring R, Load is F is W and k is 3k
Therefore, e= W/ 3k
For P or Q, the load is W/2 and spring constnt is k.
Therefore, e= W/2 /k or W/2k
The Overall extension of P and Q is just one of there extensions.. Therefore, total extension is extension of R plus extension of either P or Q.. W/3k + W/2k = 5/6W ..

 

[Monojit Saha]

MJ 12

please help
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf Q23 A

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf Q12 A
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf Q12 B

MJ 12 Nmber 12:
First, we find the common acceleration,
From the two formulas: ( linek in Mechanics)
T- 800= 80a
1200-T= 120a
We get acceleartion = 2.
We kno that in case of pulley, the distance moved by man up is equal to the distance fallen by the bag, thus the two will come to the same height after travelling half the way, i.e. 9m of the 18m.
Thus, in case of the man or bag, v2 = u2 + 2as u is 0 and the s is taken to be 9m.. which gives us 6ms-1.

 

[Monojit Saha]

please help
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf Q23 A

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf Q12 A
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf Q12 B

OCT 09 11 Number 12
The angle that T1 makes with R is greater than the angle that T2 makes with R.
R has to be balanced by the horizontal componts of T1 and T2..
Let the angle be @
R= T1cos@ + T1cos@ and R= T2cos@ + T2cos@
We can see that for cos,, the greater the angle.. less the value of cos@.. so in order to cancel out R the value of T1 must be greater as cos @is less in diagram 1. Therefore T1>T2 ..

 

[hela]

please help
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A

 

[h4rriet]

please help
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf Q32 B
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf Q7 D Q13 D Q25 D Q31 A

13. The gravitational pull is the same everywhere on Earth because the mass is the same and so is g.
25. 1/4 lambda in tube X is f. 1/4 lambda is tube Y will be x. Cross multiply to get x=2.
31. Not B because a wire is not a magnet, not C because there is always motion, not D because it's the atoms that are stationary and not the electrons.

 

[bogus]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_11.pdf
q27 h4rriet

 

[abruzzi]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_11.pdf
Please help me with question no. 10.. I don't know how to solve it

 

[Mairaxo]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf
q27 h4rriet

the spacing is very small so smallest wavelength needed. X ray has shortest wavelength amongst the 4 options.

 

[Mairaxo]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_11.pdf
Please help me with question no. 10.. I don't know how to solve it

momentum is M1V1-M2V2
that is 60m-40m=20m
elastic collision occurs as it is frictionless. M doubled as they stick to eachother so speed halves. 20/2=10
OR just use any value for mass and calculate. For example, mass=10kg. Then before collision momentum= (60*10)-(40*10)=200
after collision should also be 200kgms-1 so mass*velocity=200
as the 2 masses stick the mass is now 10+10 = 20kg
so velocity = 200/20=10