AS Physics P1 MCQs Preparation Thread.

[Abu mota]

hm okay so basically there are 2 factors that affect the R, which drops the V.
the factors are : length of wire current has travelled through and the resistivity of the wire
since the rate of current passing through the wire is always the same under same resistivty so we know gradient will be a constant.
Since the change in resistivity is descrete not continuous so there will be sudden gradient change between P1 P2 and P2 P3

tyvm, i understand it now.

 

[6Astarstudent]

tyvm, i understand it now.

np, good luck on exam! I'm having mine tomorrow, hopefully I'll get 90%+ this time

 

[Dukeofwin]

Thanks

ok, first count the number of spaces between P and XY, you will find that you will find 3 spaces, each space represents wavelength. t=wavelength/speed and so the answer is C

What do you mean by SPACES?

 

[1357913579]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf
28 of this
iam confused by spacing isnt increasing spacing means increasing the size of the hole?

 

[Tkp]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
28 of this
iam confused by spacing isnt increasing spacing means increasing the size of the hole?

here spacing means width of the slit

 

[1357913579]

here spacing means width of the slit

u mean slit seperation right? the one in the formula lamda=ay/n in this 'a' right?

 

[Tkp]

yup.l=ax/d

u mean slit seperation right? the one in the formula lamda=ay/n in this 'a' right?

 

[Sajeeb Chowdhury]

ny please.....

 

[rockerkunal]

please help!

 

[rockerkunal]

ny please.....

View attachment 28846

duuude, easy. full wave length from the diagram is six blocks, means 6x0.2ms, so 1.2ms, so 1.2x10^-3, but f=1/T f=1/1.2x10^-6, you will get 833.33 so about 830hz, is that the right answer?

 

[6Astarstudent]

ny please.....

View attachment 28846

ok each ocsillation occupies 6 squares so 0.2msx6= 1.2ms = 1.2x10^-3 s
f = 1/T = 1/(1.2x10^-3) = 830
answer is B

 

[6Astarstudent]

please help!

first we find the resistance of the wires
0.005 x 800 =4 and because there are 2 wires which forms the loop so 4x2 = 8
now we find the V dissipated by the resistance so V= IR = 8x0.6 = 4.8V
this means that 4.8 will be lost during transmission
and the relay requires 16, so 16+4.8 = 20.8

 

[Obsidian Fl1ght]

first we find the resistance of the wires
0.005 x 800 =4 and because there are 2 wires which forms the loop so 4x2 = 8
now we find the V dissipated by the resistance so V= IR = 8x0.6 = 4.8V
this means that 4.8 will be lost during transmission
and the relay requires 16, so 16+4.8 = 20.8

Excuse me 6Astarstudent... did u take ur physx p1 just now?
If so, and if u have the temperament to do so, can u kindly PM me the answers u remmbr?

 

[6Astarstudent]

Excuse me 6Astarstudent... did u take ur physx p1 just now?
If so, and if u have the temperament to do so, can u kindly PM me the answers u remmbr?

hey sorry, I'm sitting the exam tomorrow.

 

[x-gamer-x]

help needed
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_1.pdf

Q9
Q18

Thanks in advance

 

[rockerkunal]

first we find the resistance of the wires
0.005 x 800 =4 and because there are 2 wires which forms the loop so 4x2 = 8
now we find the V dissipated by the resistance so V= IR = 8x0.6 = 4.8V
this means that 4.8 will be lost during transmission
and the relay requires 16, so 16+4.8 = 20.8

thanks buddy, i had forgotten about the other wire

 

[Obsidian Fl1ght]

np, good luck on exam! I'm having mine tomorrow, hopefully I'll get 90%+ this time

My bad. I hadn't paid attention to this post of urs.
Best of luck for tomorrow!

 

[Obsidian Fl1ght]

hey sorry, I'm sitting the exam tomorrow.

Np.
Tell me how ur ppr goes then...
And out of pure curiosity, what variant are u taking?

 

[rockerkunal]

help needed
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_1.pdf

Q4
Q18

Thanks in advance

q4, its C, the division is by 0.4
and 18, i think its just mgh? i 780J, post the answers

 

[6Astarstudent]

help needed
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_1.pdf

Q4
Q18

Thanks in advance

#4
there are 5 divisions between 2-4 so each division is 0.4mA
the pointer passes roughly 3.5 marks so 0.4x3.5 = 1.4mA
1.4+2 = 3.4mA answer is C

#18
Ep=mgh = 50x9.81x1.6=784.8 so answer is C