AS Physics P1 MCQs Preparation Thread.

[6Astarstudent]

tyvm, i understand it now.

np, good luck on exam! I'm having mine tomorrow, hopefully I'll get 90%+ this time

 

[Dukeofwin]

Thanks

ok, first count the number of spaces between P and XY, you will find that you will find 3 spaces, each space represents wavelength. t=wavelength/speed and so the answer is C

What do you mean by SPACES?

 

[1357913579]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf
28 of this
iam confused by spacing isnt increasing spacing means increasing the size of the hole?

 

[Tkp]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
28 of this
iam confused by spacing isnt increasing spacing means increasing the size of the hole?

here spacing means width of the slit

 

[1357913579]

here spacing means width of the slit

u mean slit seperation right? the one in the formula lamda=ay/n in this 'a' right?

 

[Tkp]

yup.l=ax/d

u mean slit seperation right? the one in the formula lamda=ay/n in this 'a' right?

 

[Sajeeb Chowdhury]

ny please.....

 

[rockerkunal]

please help!

 

[rockerkunal]

ny please.....

View attachment 28846

duuude, easy. full wave length from the diagram is six blocks, means 6x0.2ms, so 1.2ms, so 1.2x10^-3, but f=1/T f=1/1.2x10^-6, you will get 833.33 so about 830hz, is that the right answer?

 

[6Astarstudent]

ny please.....

View attachment 28846

ok each ocsillation occupies 6 squares so 0.2msx6= 1.2ms = 1.2x10^-3 s
f = 1/T = 1/(1.2x10^-3) = 830
answer is B

 

[6Astarstudent]

please help!

first we find the resistance of the wires
0.005 x 800 =4 and because there are 2 wires which forms the loop so 4x2 = 8
now we find the V dissipated by the resistance so V= IR = 8x0.6 = 4.8V
this means that 4.8 will be lost during transmission
and the relay requires 16, so 16+4.8 = 20.8

 

[Obsidian Fl1ght]

first we find the resistance of the wires
0.005 x 800 =4 and because there are 2 wires which forms the loop so 4x2 = 8
now we find the V dissipated by the resistance so V= IR = 8x0.6 = 4.8V
this means that 4.8 will be lost during transmission
and the relay requires 16, so 16+4.8 = 20.8

Excuse me 6Astarstudent... did u take ur physx p1 just now?
If so, and if u have the temperament to do so, can u kindly PM me the answers u remmbr?

 

[6Astarstudent]

Excuse me 6Astarstudent... did u take ur physx p1 just now?
If so, and if u have the temperament to do so, can u kindly PM me the answers u remmbr?

hey sorry, I'm sitting the exam tomorrow.

 

[x-gamer-x]

help needed
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_1.pdf

Q9
Q18

Thanks in advance

 

[rockerkunal]

first we find the resistance of the wires
0.005 x 800 =4 and because there are 2 wires which forms the loop so 4x2 = 8
now we find the V dissipated by the resistance so V= IR = 8x0.6 = 4.8V
this means that 4.8 will be lost during transmission
and the relay requires 16, so 16+4.8 = 20.8

thanks buddy, i had forgotten about the other wire

 

[Obsidian Fl1ght]

np, good luck on exam! I'm having mine tomorrow, hopefully I'll get 90%+ this time

My bad. I hadn't paid attention to this post of urs.
Best of luck for tomorrow!

 

[Obsidian Fl1ght]

hey sorry, I'm sitting the exam tomorrow.

Np.
Tell me how ur ppr goes then...
And out of pure curiosity, what variant are u taking?

 

[rockerkunal]

help needed
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_1.pdf

Q4
Q18

Thanks in advance

q4, its C, the division is by 0.4
and 18, i think its just mgh? i 780J, post the answers

 

[6Astarstudent]

help needed
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_1.pdf

Q4
Q18

Thanks in advance

#4
there are 5 divisions between 2-4 so each division is 0.4mA
the pointer passes roughly 3.5 marks so 0.4x3.5 = 1.4mA
1.4+2 = 3.4mA answer is C

#18
Ep=mgh = 50x9.81x1.6=784.8 so answer is C

 

[6Astarstudent]

Np.
Tell me how ur ppr goes then...
And out of pure curiosity, what variant are u taking?

variance 3, so taking paper 13