• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

As physics p1 MCQS YEARLY ONLY.

Messages
142
Reaction score
135
Points
53
In my opinion it'd be best if you simply ask specific questions you have trouble with. Doesn't make much sense for me to do a whole paper just in case some of them are difficult. If I do a question it should be one that benefits others...
May/June 2011 Paper 11 Questions 13 , 14 , 27, and 36 please.
 
Messages
51
Reaction score
18
Points
18
A 327.7ms–1 B 328ms–1 C 330ms–1 D 300ms–1Which of the following gives her result expressed to the appropriate number of significant figures? A student makes measurements from which she calculates the speed of sound as 327.66ms–1. She estimates that her result is accurate to ±3 %.
 
Messages
142
Reaction score
135
Points
53
Screen Shot 2015-12-20 at 7.48.55 PM.png


I think you meant this one Syed Umar ?

Well, the reasoning is that uncertainty is always expressed to 1 significant figure. So, 3% of 327.66 m/s is 10m/s , if you round off to 1 significant figure.
Therefore, the speed should be expressed to the nearest 10, which is the choice C.

I hope I have answered your question satisfactorily :D
 
Messages
51
Reaction score
18
Points
18
View attachment 58100


I think you meant this one Syed Umar ?

Well, the reasoning is that uncertainty is always expressed to 1 significant figure. So, 3% of 327.66 m/s is 10m/s , if you round off to 1 significant figure.
Therefore, the speed should be expressed to the nearest 10, which is the choice C.

I hope I have answered your question satisfactorily :D
Ohhh, THANKS! :D
 
Messages
140
Reaction score
414
Points
73

Q4: D

They've given us the frequency = 5 Hz
From that, we calculate the time period = 1/f = 0.2 s

Now, from the graph, we know that there is one complete wave in 2 divisions on the time axis.
0.2 s => 2 divisions
1 div => 0.2/2 = 0.1 s

But, the answers are in ms so we need to convert our s value.
0.1 s = 0.1*10^3 ms = 100 ms

Q3 I'm not getting it either :p will let you know when i do.
 
Messages
1,394
Reaction score
12,123
Points
523
Q4: D

They've given us the frequency = 5 Hz
From that, we calculate the time period = 1/f = 0.2 s

Now, from the graph, we know that there is one complete wave in 2 divisions on the time axis.
0.2 s => 2 divisions
1 div => 0.2/2 = 0.1 s

But, the answers are in ms so we need to convert our s value.
0.1 s = 0.1*10^3 ms = 100 ms

Q3 I'm not getting it either :p will let you know when i do.
Q:3 : the distance is measure as before. So d will not change. Let the value of the new constant be Kx.
the new equation will be: d = KxV^2
convert the V in this equation to km/h :
d = Kx (1/1000 * 3600)^2
d = 12.96Kx

^substitute this into the original given equation, you'll get:

12.96Kx = k1 v^2

v^2 = 1
so,

12.96Kx = K1
Kx = 0.077162 K1 ~ 0.0772 K1 Ans.

So A is the answer.
 
Messages
140
Reaction score
414
Points
73
Q:3 : the distance is measure as before. So d will not change. Let the value of the new constant be Kx.
the new equation will be: d = KxV^2
convert the V in this equation to km/h :
d = Kx (1/1000 * 3600)^2
d = 12.96Kx

^substitute this into the original given equation, you'll get:

12.96Kx = k1 v^2

v^2 = 1
so,

12.96Kx = K1
Kx = 0.077162 K1 ~ 0.0772 K1 Ans.

So A is the answer.

Oh right! I used 60 instead of 3600 by mistake. :p Thanks man!
 
Top