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As physics p1 MCQS YEARLY ONLY.

A*(a*)

A*(a*)

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Gémeaux said:
The answer to this is C. Electric field strength is *Uniform* between two parallel plates, so from X to Y, the value of E remains same which is shown by graph in option C.
Click to expand...

Oh man! it says the distance "alongggg! the line XY" i should have noticed that! along XY it would be constant! but increasing the length of XY would decrese E.field na?
 
bogus

bogus

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leosco1995 said:
OK here's all of June 2002.

June 2002
==========

1. B

Fact. A would be right if K was given instead of °C.

2. B

You go FORWARD in the direction of X and BACKWARD in the direction of Y.

3. A

The units of speed (msˉ¹)s are equal on both sides.

4. B

You can eliminate A, C and D because they are all nonsense (in my opinion). B is correct because if the timer was started and THEN the ball thrown, you would get 0

height for some time 't' on the x-axis.

5. C

Uncertainity = 2(0.03) + 0.02 = 0.08 = 7%. You multiply the uncertainty of V twice because of the square.

6. D

Air resistance isn't negligible because the speed eventually becomes constant (terminal velocity), so rule out A and C. The Y-axis can't be distance because it

eventually becomes constant, the distance can't become constant during the fall of a body. :p

7. A

Acceleration is constant with uniformly increasing speed. B is increasing rate of speed, C is constant speed and D is at rest.

8. D

S is the distance from cliff to highest point. R is the distance from highest point to sea-level. We are looking for the distance of sea-level to cliff, which is R -

S.

9. B

K.E is ALWAYS conserved in elastic collisions, so K.E before impact is 0.5mv² + 0.5mv² = mv². That means after impact, the K.E should also be mv².

10. B

Fnet = ma.
12 - x = 4 * 0.6
x = 9.6 N.

11. B

Momentum is always conserved so forming an equation,
0 = M1V1 + M2(-V2)
M1V1 = M2V2
V1/V2 = M2/M1

12. D

Fact. Upthrust is very small compared to weight. Also, drag is almost as large as weight not they are not the same (weight is a bit larger) so A and B are wrong.

13. C

Torque = 2 * PD

To find the perpendicular distance, find the perpendicular distance from the force to the pivot and then multiply that by 2. To find the distance from the force to

pivot, construct a triangle and obtain the equation x = 0.15 sin 30.

14. C

Upthrust is the pressure of the block (Pb - Pt) * area, I think.

15. D

Resolve the horizontal 3N and vertical 4N force to get a sideways 5N force which is in the same line as the diagonal 4N force. The resultant force has a magnitude of

1N and the direction is towards the upper-right.

16. D

Efficiency = (useful output)/(total input)

17. C

The only work done is reducing the volume, and since the pressure is constant, work done is p(V1 - V2).

18. B

At Q, the potential energy is 50kJ less than P. This means that the 50kJ must have been converted to kinetic energy. So, K.E (Q) = K.E (P) + 50kJ = 55kJ. And 10 was

lost in friction, leaving us with 45 kJ.

19. D

Simple Power = Force * Velocity.
24 * 10³= 600 * V

20. B

Evaporation occurs over a range of temperatures, while the rest only occur at a fixed temperature.

21. A

Total density = total mass / total volume.

The total mass is m1 + m2 = 2m (since they are equal).

The total volume is MD1/MD2. D1 is ρ and D2 is 2ρ, and that gives us the total volume has 3M/2ρ. Then just use the total density formula I wrote above.

22. C.

Stress = F/A
Strain = extension/length
YM = stress/strain.

23. B

Simple ratio stuff with the YM formula FL/Ax.

24. B

Area below a force/extension graph is energy (i.e. work done). In reducing l2 to l1, this part of the graph is MNQP.

25. C

Speed of electromagnetic waves is always constant, but the frequency will decrease because the wavelength increases.

R M I V U X Y

--> increasing frequency
<-- increasing wavelength

26. B

λ = 4cm.
Time period for one wave is therefore 4 * 0.002s = 0.008s.
F = 1/T = 125 Hz.

27. B

Fact. I α a² and I α 1/r².

28. C

Use the path difference formula (distance from one source - distance from other source) to create an equation involving X. S2x - S1X = λ/2. λ/2 because X is a minimum point.

29. D

λ = 2(1.5) = 3m. 2 nodes are 0.5λ apart.

v = fλ
v = 300(3) = 900.

30. B

Graph X - Diode
Graph Y - Ohmic conductor/metal wire
Graph Z - Lamp

You have to learn these I/V graphs. Also note that a thermistor/semi-conductor has a graph which is like the lamp but has an increasing gradient instead.

31. C

Basic formula recall needed here.

32. A

R = V²/R = 240²/100 = 576. However, this is when the filament is heated so it has increased by 16 times. The normal room temperature would therefore be 576/16 = 36.

33. C

Basic Kirchoff's first law.

34. C

Diagram 2 has the same setup as diagram 1 (2 lamps connected in each parallel setup). If you are confused about diagram 2, then just rotate it. Since they have the same setup, the brightness would obviously be the same.

35. C

The way I solved this was by trying each option until I calculated a 2V drop at R1 and 1V drop at R2. Find the total current using V = IR (where V is 5 and the total resistance is the sum of R1, R2 and R3) and then use the formula again at each resistor to find the voltage drop (5 - V).

36. A

The electron will accelerate towards the +ve plate so A. A is +ve because the field lines are directed from +ve to -ve.

37. A

E = V/d

Increasing the value of 'd' will decrease the value of 'E'. Therefore A is correct.

38. C

Fact.

39. A

Basic stuff. :p

40. C

Work backwards to figure this one out, and see what is happening to the nucleon number and proton number individually. Then # of neutrons is nucleon number - proton number.

November 2002 will probably come next, and then I'll do 2011 backwards.
Click to expand...
i dont get question 28 and also plz do november 2002 question 35. Help is appreciated deeply:)
 
h4rriet

h4rriet

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magnesium said:
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf
Q 6,10,11,15,21,25,40
Click to expand...

11. Mass is conserved; it always is. The initial and final speeds are the same, so the speed too is conserved. If the mass and speed are the same, then the k.e. too is the same. That leaves momentum.
15.
73nvup.jpg

21. Efficiency = Power output/Power input. Power output=200 x 6000. Power input=500 x 9.81 x 300.
25. E=FL/Ae. L is proportional to e; A is inversely proportional to e; E is inversely proportional to e. The steel wire has twice the length, so 2e, 1/4th the area, so 8e, and twice the E, so 4e.
40.
anlzrs.jpg
 
h4rriet

h4rriet

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A*(a*) said:
View attachment 23529 View attachment 23528
Click to expand...
31. Electric fields are uniform between two parallel plates.
30. E=V/d. D is irrelevant. C: if the resistance of the resistor is increased, it'll take more voltage for itself. That'll decrease the voltage across the plates, and therefore the E. B: an increase in the PD will lead to an increase in the E. A: a decrease in the distance will lead to an increase in E because E is inversely proportional to d.
 
h4rriet

h4rriet

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hela said:
CAN U SOLVE
View attachment 27303
Click to expand...
A is wrong because the GPE does not increase.
B is correct; it loses GPE and gain EPE because the pressure increases with depth; WD on a fluid = pressure x delta volume = EPE.
C is incorrect; it loses GPE but does not gain KE because the question states that the rate of flow is constant.
D is incorrect; it gains EPE because the pressure INCREASES.
 
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