We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
As stated in the question, the liquid in vessel P is twice as dense as the liquid in vessel Q.
8)I want you to check out my signature..
If you don't know many concepts than visit Khan academy
So here is your solutions, sorry for late as I was on date with chemistry
10)
Does weight change if a force is exerted on it?
No - Basic thing
35)
Whats wrong, we just need to compare :¬
For original wire :
Area = Π * r ^ 2 right ? ( I assumed d/2 as r )
length = l
resisitivity = ρ
Resistance = R
For replacement wire :
Area = Π * 4r ^ 2
length = l
resistivity = 2ρ
Now compare original with replacement wire :
Original :
ρl/Π * r ^ 2 --> R
so for replacement wire :
2ρl/ Π * 4r ^ 2 = R/2
37) This was also an easy one
-->So it will decrease less after passing through 2 ohm than when passing through 4 ohm
- After voltage passes through some resistance it will decrease
- The higher the resistance the greater the decrease in voltage
Hence it is D
ote="Zepudee, post: 814292, member: 97182"]http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_12.pdf
Q8,36?
:¬ ?[/quote]
8)
I hope that your are familiar with Equations for linear motion. ( Do not confuse with Newton's laws of motion). They are:
1) v = u + a*t
2) s = u*t + 1/2 *a*t^2
3) 2*a*s = v^2 - u^2
Here v stands for final velocity, u stands for initial velocity, s means displacement, t stands for time and a means acceleration.
We are given that:
t = 0.5 seconds
a= 9.8 meters per second square ( As the experiment is taking place on earth, so we consider acceleration due to gravity)
u = 0 ( as the feather is dropped from rest )
Now we apply second equation of motion.
s = u*t + 1/2 *a*t^2
s = 0*0.5 + 1/2*(9.8)*0.5*0.5
s = 1.225 m, which is approximately 1.3.
36) This is also a concept, we dont have fix values of currents, it varies, so we took a mean of power
Find power at -1 and then at 2
For -1 :
P = 100W
For 2 :
P = 400W
Now as current is varying we have to take mean value of power : i.e 400 +100 = 500 / 2 = 250W
Shamajh aya
Just be calm when you solve physics, they have so many easy twists
Again, Just a logic. I don't have time, so took credits.
Ah, I misread the marking scheme!!As stated in the question, the liquid in vessel P is twice as dense as the liquid in vessel Q.
We know that pressure = density × acceleration due to gravity × height/depth.
So pressure in P = 2×density×acceleration due to gravity × height
Pressure in Q = density×acc. Due to gravity × height
By taking the the ratio of the quantities we are left with 2\1 I.e A.
Thanks so much for the time, I really appreciate it!
Again, Just a logic. I don't have time, so took credits.
But in my way, hope you get it
15)
When a total amount of work W is done on any object, the kinetic energy of that object changes by a quantity W - if negative work is done on the object, the kinetic energy changes by a negative amount and if positive work is done on the object it's energy changes by a positive amount.
Suppose you throw an object upwards, gravity is the only force that does any work on the object. That work is negative, so the kinetic energy of the object decreases until the object comes to a stop. When it falls down, gravity does positive work on the system thus increasing it's kinetic energy.
In this case, taking the first situation, the force is constant at magnitude F, over the entire displacement s. Thus, the work done by that force is Fs. By the
Work-Kinetic Energy theorem, this is equal to the increase in kinetic energy of the system. This value is given as 4 Joules (8-4 = change in KE = +4 Joules).
In the upcoming situation, the force is 2F, displaced through a distance 2s. Thus, the total work done is 4Fs. This is also the change in kinetic energy of the object.
From above, we know that Fs is 4 Joules, so 4Fs = 4*4 = 16 Joules increase. From 4 Joules, the increase of 16 Joules takes it to 20 Joules = B.
Numeric way explanation :
When the force = F, and distance = s, work done = Fs.
Since work done = K.E. gain → Fs = 8-4 = 4J
Fs = 4J
So, when force = 2F, and distance = 2s, work done = 2F * 2s →4Fs.
Since Fs = 4J, 4Fs = 4 * 4 = 16 J.
So gain in K.E. = 16 J.
And since the kinetic energy already equals 4 J....the new K.E. = 4 + 16 → 20 J
Hence you get answer as B
26)
As shown in the fig, at time = 18 s, phase diff b/w the 2 waves = 180° or π.
1 wavelength = 360°
So, 1/8 of a wavelength = 360°/8 → 45°.
Phase diff = 180° at 18 s.
So, phase diff = 45° at x.
x = (18 * 45)/180
x = 4.5 s
Or Just you can think it this way :¬
At 18 second, the phase difference in 1/2 of the cycle, so at what time will the phase difference be 1/8? just try normal proportionation
Hence answer is B
And YUP, i understand now Didnt know it is just like that, I kept making it harder for myself.
That is the problem, we complicate things.Wow, Thank you for typing all this out for me. I really appreciate
Well I am busy, will post answers after 1 hour, k ?
Q.8
8)
Solve Q35
I am feeling this are some hard.
If der r 2 or more wires protruding from a single point, then da current is split. When current is split, da value of current is not da same everywhere in da circuit. Da only circuit arrangement, where dis is not da case is arrangement D. In D, a single wire is connecting every meter, so current is same throughout circuit
question number ?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now