- Messages
- 5
- Reaction score
- 19
- Points
- 3
As stated in the question, the liquid in vessel P is twice as dense as the liquid in vessel Q.
We know that pressure = density × acceleration due to gravity × height/depth.
So pressure in P = 2×density×acceleration due to gravity × height
Pressure in Q = density×acc. Due to gravity × height
By taking the the ratio of the quantities we are left with 2\1 I.e A.