As physics p1 MCQS YEARLY ONLY.

[Abdul Aziz Jamil]

M/J 13 paper 12
Q 14 and Q 16

 

[Abdul Aziz Jamil]

May June 2014
Paper 11 Q 12
How to solve?

 

[A41905]

anyone has answer for Nov 03

 

[A41905]

can someone explain number 10 (june 2009)?
Isn't (0.5 x m x 2v^2) / (0.5 x 2m x v^2) equals to 1mv^2/1mv^2?
Then shouldnt the answer be 1?
I dont understand the calculation... pls help me!!!
Thx in advance!

 

[The Sarcastic Retard]

can someone explain number 10 (june 2009)?
Isn't (0.5 x m x 2v^2) / (0.5 x 2m x v^2) equals to 1mv^2/1mv^2?
Then shouldnt the answer be 1?
I dont understand the calculation... pls help me!!!
Thx in advance!

Pi=Pf
0 = 2mVy - mVx
Vx = 2Vy
KEx = 1/2 * m * (2Vy)^2
KEy = 1/2 * 2m * (Vy)^2
Till this u are correct, the calculation mistake u did is; 0.5 * 4 * mVy^2 = 2mVy^2 not 1mVy^2
X/Y = 2mVy^2 / mVy^2 = 2/1

 

[FranticAmaze]

a_wiserME!! NotYourType ruby_fern Midnight dream

 

[jesse d]

When u have 2 vectors, look at their ' x ' n ' y ' directions. If both point in 1 direction, then da resultant will also point in dat direction. If dey point in opposite directions, den da vector whose component is bigger will give da resultant direction.
So here both X n Y r pointing towards da right of P, so da resultant will also point towards da right of P

 

[A41905]

for June 2007, Question 3
Answer is A.

Units for:
speed, v is ms^-1
density is kgm^-3
acceleration, g is ms^-2
depth, h is m
wavelength is m.

Therefore, by substituting the units in the equation, you should be able to get one homogenous equation which is A.
v = (g x lamda)^1/2
ms^-1 = (ms^-2 x m)^1/2
ms^-1 = (m^2.s^-2)^1/2
ms^-1 = ms^-1

*Note that ^1/2 means square root.

Hope this helps. Pls correct me if I'm wrong.

 

[Jun Min]

consine rule formula is a^2 = b^2+c^2 -2 b c cos theta..

 

[The Sarcastic Retard]

consine rule formula is a^2 = b^2+c^2 -2 b c cos theta..

so?

 

[Minnah90]

November2011

Come on, why not keep this going guys?

 

[Minnah90]

Go to
http://physics-ref.blogspot.com/

Thanks, hope there are discussions as well.

 

[Akshajistari]

Could someone please do 2011- 2015 ?
I know I sound so whiney
sj0007 qwertypoiu My Name Midnight dream FranticAmaze nehaoscar

http://physics-ref.blogspot.com/ only has the second variants for most years

 

[sj0007]

Could someone please do 2011- 2015 ?
I know I sound so whiney
sj0007 qwertypoiu My Name Midnight dream FranticAmaze nehaoscar

http://physics-ref.blogspot.com/ only has the second variants for most years

I didn't do many........ Only till 2013 and that too first variants........ The others I am keeping for later practice when I do proper past papers with timings and stuff........ So I can help u till that if u want
Aww no u don't.......... I find physics hard too

 

[Akshajistari]

I didn't do many........ Only till 2013 and that too first variants........ The others I am keeping for later practice when I do proper past papers with timings and stuff........ So I can help u till that if u want
Aww no u don't.......... I find physics hard too

Yes please! That would be an enormous amount of help

 

[sj0007]

Yes please! That would be an enormous amount of help

Hehe, okay so how exactly am I supposed to help u with the questions? Clear ur doubts??

 

[qwertypoiu]

Could someone please do 2011- 2015 ?
I know I sound so whiney
sj0007 qwertypoiu My Name Midnight dream FranticAmaze nehaoscar

http://physics-ref.blogspot.com/ only has the second variants for most years

In my opinion it'd be best if you simply ask specific questions you have trouble with. Doesn't make much sense for me to do a whole paper just in case some of them are difficult. If I do a question it should be one that benefits others...

 

[sj0007]

In my opinion it'd be best if you simply ask specific questions you have trouble with. Doesn't make much sense for me to do a whole paper just in case some of them are difficult. If I do a question it should be one that benefits others...

That's a good point....... Annnd I guess that's exactly what's going to be beneficial for some of the others and well as for Akshajistari

 

[Akshajistari]

Sure! I will ask soon