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bio mcq....?

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this question is completely wrong i guess......in all past papers i solved its written percentage tranfer of energy is 10 percent but........how the hell this fuking cambridge gives such a damn question...chek wat thte hell er says.
"The percentage transfer between the Sun and producers was 1%, between the producers and primary
consumers is 10%, between the primary consumers and secondary consumers is 20% and between detritus
and decomposers is 80%.
wtf is thisss
 
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hassam said:
this question is completely wrong i guess......in all past papers i solved its written percentage tranfer of energy is 10 percent but........how the hell this fuking cambridge gives such a damn question...chek wat thte hell er says.
"The percentage transfer between the Sun and producers was 1%, between the producers and primary
consumers is 10%, between the primary consumers and secondary consumers is 20% and between detritus
and decomposers is 80%.
wtf is thisss

quit freaking cursing.
In our mind, we always think that from each level to another level it would be 10%. This is not true. The 10% is the overall efficiency of transfer of energy from the producer to primary consumer (in the textbook, it says that it is rarely greater than 10% , pp 93). That means 10% is from producer to 1’ consumer.

Now, let’s look at the percentage transfer between sun and producer. On pp 92, you will see that it says in most ecosystem, the plants convert less than 3% of this sunlight to chemical energy and later on, reasons are being given. So we can assume that percentage transfer, will be greatest, 3%, where in the question, 1% is the nearest answer.

For percentage of 1’ to 2’, it’s 20% and in between detritus and decomposer, it would be 80%. That’s a theory that we can memorize.

But if we look at question 38 from M/J 2010 Paper 11, we calculate with 10% efficiency of energy transfer between trophic levels, cause the question itself says so.

So, for question that specifies the percentage energy transfer, then, we use the figure provided. If not, then we have to memorise the different of efficiency of energy transfer between each trophic levels.
Sun à producer – less than 3%
Producer à 1’- less than 10%
1’ à 2’ - less than 20%
Detritus à decomposer – less than 80%

SO SHUT UP!
 
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that detritus thing u said is not in the options dude so what is this........
 
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Xthegreat said:
hassam said:
this question is completely wrong i guess......in all past papers i solved its written percentage tranfer of energy is 10 percent but........how the hell this fuking cambridge gives such a damn question...chek wat thte hell er says.
"The percentage transfer between the Sun and producers was 1%, between the producers and primary
consumers is 10%, between the primary consumers and secondary consumers is 20% and between detritus
and decomposers is 80%.
wtf is thisss

quit freaking cursing.
In our mind, we always think that from each level to another level it would be 10%. This is not true. The 10% is the overall efficiency of transfer of energy from the producer to primary consumer (in the textbook, it says that it is rarely greater than 10% , pp 93). That means 10% is from producer to 1’ consumer.

Now, let’s look at the percentage transfer between sun and producer. On pp 92, you will see that it says in most ecosystem, the plants convert less than 3% of this sunlight to chemical energy and later on, reasons are being given. So we can assume that percentage transfer, will be greatest, 3%, where in the question, 1% is the nearest answer.

For percentage of 1’ to 2’, it’s 20% and in between detritus and decomposer, it would be 80%. That’s a theory that we can memorize.

But if we look at question 38 from M/J 2010 Paper 11, we calculate with 10% efficiency of energy transfer between trophic levels, cause the question itself says so.

So, for question that specifies the percentage energy transfer, then, we use the figure provided. If not, then we have to memorise the different of efficiency of energy transfer between each trophic levels.
Sun à producer – less than 3%
Producer à 1’- less than 10%
1’ à 2’ - less than 80%
Detritus à decomposer – less than 20%

* amends ( typed the other way round )
- primary to secondary is less than 80% ( the efficiency from 1 - 2 should be the highest as very little energy is left )
- detritus to decomposer is less than 20%
 
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