- Messages
- 582
- Reaction score
- 113
- Points
- 53
40. the logic here is dat as one exercise the amplitude of the wave ll increase ie tidal volume ll increase (the volume of air that is inspired or expired in a single breath during regular breathing) because depth of breathing increases – panting! 
so naturally the area bove and below the graph ll decrease ans A
38.
A The tendons of the heart valves are weakened by blood being forced back through the bicuspid/left atrio-ventricular valve into the left atrium.
the semi lunar valve opening is narrow which is in the aorta so there is no link watsoevr 2 da bicuspid valve which is in left side of the heart and there is no bak flow into atriu 2
this option is therefore senseless!
B The cardiac muscle of the left ventricle wall is thinned by blood leaking out of the left ventricle during ventricular diastole.
Y on earth would the wall of ventricle b thinned even if the blood leaks? And how can blood leak 4m ventricle? So again it is senseless may b more so than A
C There is less cardiac muscle in the left ventricle and reduced diastolic blood pressure, caused by the smaller blood volume entering the left atrium.
The bicuspid valve is working normally so the blood volume in left ventricleis just fine thanku very much! And there is no less cardiac muscle and reduced diastolic pressure and blah blah blah
D The wall of the left ventricle thickens, leading to an enlarged heart and inability to relax and fill completely during diastole.
BINGO! The thing is dat… dat since the opening of the semilunar valve is small… all the blood pumped by the ventricle does not enter the aorta and builup of pressure in ventricle bcuz of that leads to enlargement of heart and inability 2 relax and so on….
U HV 2 C WHERE DA THING CONCERNED IS LOCATED AND THEN TRY 2 MAKE LOGIC!
28
A Amylose has a branched structure and amylopectin is coiled to give a compact molecule for transport.
B In the breakdown of amylose and amylopectin, many hydrolysis reactions release stored energy.
C In the formation of amylose and amylopectin, many condensation reactions allow the release of stored energy.
D The final amylose / amylopectin complex is insoluble and does not affect the osmotic
properties of the cell.
Function of starch is as an energy STORE it must be in the form that it does not allow osmotic changes (changes in water potential) and according to this fact option D is rite
Besides option C is so totally wrong bcuz condensation reaction cant release energy at least not in this case
23
Its 1 If u look into chapter of meiosis (A2) of Mary Jones CIE endorsed book there is a small topic on sickle cell anaemia and also on mutations it can clear ur concepts better than me. If u don’t get it tell me I’ll try 2 xpln! A
21
Again I suggest da diagram in mary jones in the chapter 6 of cell division
Its summarized chromatids separate and move to the opp poles C
20
I believe u can solve this now after hassum’s precise upload
The sequence is this
S P T Q R dats C
13 I division on stage micrometer is .1 mm and is represented by 40 divisions of graticule
0.1 -------------------------- 40 x-----------------------------100(100 divisions of graticule make up the diametre) x = 10/4o mm = .25 mm
Diameter = .25 mm radius is .125 mm
Area is πr2 = 0.125 × .125 × π = .0490 mm
I mm is 1000 micrometre
So × the area by 1000000 and the ans is C
9 denytrifying bacteria always give their end product Nitrogen gas
This eliminates option A and D
Decomposing bacteria always convert proteins carbohydrates and lipids into their respective ions ie 3 here
U r left with nitrifyin bacteria it makes NO3- ions 4m NH4+ ions and for future ref u can again look into the flow chart in mary jones
Wat book do u normally refer 2???????
so naturally the area bove and below the graph ll decrease ans A38.
A The tendons of the heart valves are weakened by blood being forced back through the bicuspid/left atrio-ventricular valve into the left atrium.
the semi lunar valve opening is narrow which is in the aorta so there is no link watsoevr 2 da bicuspid valve which is in left side of the heart and there is no bak flow into atriu 2
this option is therefore senseless!
B The cardiac muscle of the left ventricle wall is thinned by blood leaking out of the left ventricle during ventricular diastole.
Y on earth would the wall of ventricle b thinned even if the blood leaks? And how can blood leak 4m ventricle? So again it is senseless may b more so than A
C There is less cardiac muscle in the left ventricle and reduced diastolic blood pressure, caused by the smaller blood volume entering the left atrium.
The bicuspid valve is working normally so the blood volume in left ventricleis just fine thanku very much! And there is no less cardiac muscle and reduced diastolic pressure and blah blah blah
D The wall of the left ventricle thickens, leading to an enlarged heart and inability to relax and fill completely during diastole.
BINGO! The thing is dat… dat since the opening of the semilunar valve is small… all the blood pumped by the ventricle does not enter the aorta and builup of pressure in ventricle bcuz of that leads to enlargement of heart and inability 2 relax and so on….
U HV 2 C WHERE DA THING CONCERNED IS LOCATED AND THEN TRY 2 MAKE LOGIC!
28
A Amylose has a branched structure and amylopectin is coiled to give a compact molecule for transport.
B In the breakdown of amylose and amylopectin, many hydrolysis reactions release stored energy.
C In the formation of amylose and amylopectin, many condensation reactions allow the release of stored energy.
D The final amylose / amylopectin complex is insoluble and does not affect the osmotic
properties of the cell.
Function of starch is as an energy STORE it must be in the form that it does not allow osmotic changes (changes in water potential) and according to this fact option D is rite
Besides option C is so totally wrong bcuz condensation reaction cant release energy at least not in this case
23
Its 1 If u look into chapter of meiosis (A2) of Mary Jones CIE endorsed book there is a small topic on sickle cell anaemia and also on mutations it can clear ur concepts better than me. If u don’t get it tell me I’ll try 2 xpln! A
21
Again I suggest da diagram in mary jones in the chapter 6 of cell division
Its summarized chromatids separate and move to the opp poles C
20
I believe u can solve this now after hassum’s precise upload
The sequence is this
S P T Q R dats C
13 I division on stage micrometer is .1 mm and is represented by 40 divisions of graticule
0.1 -------------------------- 40 x-----------------------------100(100 divisions of graticule make up the diametre) x = 10/4o mm = .25 mm
Diameter = .25 mm radius is .125 mm
Area is πr2 = 0.125 × .125 × π = .0490 mm
I mm is 1000 micrometre
So × the area by 1000000 and the ans is C
9 denytrifying bacteria always give their end product Nitrogen gas
This eliminates option A and D
Decomposing bacteria always convert proteins carbohydrates and lipids into their respective ions ie 3 here
U r left with nitrifyin bacteria it makes NO3- ions 4m NH4+ ions and for future ref u can again look into the flow chart in mary jones
Wat book do u normally refer 2???????
