Biology; Chemistry; Physics: Post your doubts here!

[Faizan Muhammmad]

okay so inthtis question he multiplies your answer with 30 on denominator and numerator ......

 

[exploded diper]

(30/120)*(29*119)

papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w08_ms_2.pdf
this is the ms

 

[Faizan Muhammmad]

papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w08_ms_2.pdf
this is the ms

what is your query or confusion?

 

[exploded diper]

what is your query or confusion?

y is it written 29k/476k instead of 29 over 476

 

[Mahnoorfatima]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Physics (5054)/5054_w09_qp_2.pdf
Question 11 b full part anyone??
ANd The EITHER ci
And OR cii and ciii

 

[Faizan Muhammmad]

y is it written 29k/476k instead of 29 over 476

dunno , cant say

 

[exploded diper]

b1...line of positive slope

b11...voltmeter reading falls...because the resistance of x decreases so does its voltage.....and since this is a series circuit so the voltage across the 16 ohem resistor decreases...

b111....0 to 9

 

[Mahnoorfatima]

ANd OCT/NOV 2012 p22 ques 2 aii . how do I draw the graph??
qs 6 part b?

 

[Faizan Muhammmad]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Physics (5054)/5054_w09_qp_2.pdf
Question 11 b full part anyone??

i) linear graph ,not starting from zero, positive gradient
temp x axis, resistance y axis
ii) voltmeter reading RISES, since temp rises due to which resistance rises
iii) 0-12

 

[Faizan Muhammmad]

b1...line of positive slope

b11...voltmeter reading falls...because the resistance of x decreases so does its voltage.....and since this is a series circuit so the voltage across the 16 ohem resistor decreases...

b111....0 to 9

your answer has got some problems mate

 

[Faizan Muhammmad]

ANd OCT/NOV 2012 p22 ques 2 aii . how do I draw the graph??

load x axis
extension y axis
(2.5,45) plot it
dra straight line passing from origin

 

[Faizan Muhammmad]

qs 6 part b?

current=charge/time
Total current *time =total charge
5.6x10^-3 * 1 = total charge

paticles = total charge / on one particle
=5.6x10^-3 / 1.6x10^-9

 

[funky brat]

current=charge/time
Total current *time =total charge
5.6x10^-3 * 1 = total charge

paticles = total charge / on one particle
=5.6x10^-3 / 1.6x10^-9

You answer all questions, leave something for us.

 

[exploded diper]

You answer all questions, leave something for us.

lol...exactly

 

[Awesome12]

You answer all questions, leave something for us.

Well we can accentuate people to ask more questions

 

[funky brat]

Well we can accentuate people to ask more questions

PEOPLE ASK MORE QUESTIONS PLEASE.

 

[Faizan Muhammmad]

You answer all questions, leave something for us.

if you say so
tag me on toughest ones then

 

[Faizan Muhammmad]

PEOPLE ASK MORE QUESTIONS PLEASE.

yeah
ANSWERS AVAILABLE FOR FREE
DONE BY THE EXPERTS IN SCIENCES
maybe we should open online academy

 

[funky brat]

yeah
ANSWERS AVAILABLE FOR FREE
DONE BY THE EXPERTS IN SCIENCES
maybe we should open online academy

Do you know any toughest questions? Can you ask me please?
P.S That's a great idea.

 

[Faizan Muhammmad]

Do you know any toughest questions? Can you ask me please?
P.S That's a great idea.

Last year some of us started a convo before papers
we shared the toughest questions and when discussion was banned during papers we discussed there (that is legit )
we can do something this time too
gather people up