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C because it's the same as the structure shown. As in, it's not branched. It's the same as the structure, the only difference being the CH3 which is rotated. It's just twisted, at the end. It's still a chain.
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the question statesC because the third one is the same as the structure shown. As in, it's not branched. It's the same as the structure, the only difference being the CH3 which is rotated. It's just twisted, at the end. It's still a chain.
the question states
Which structure is NOT an isomer
But why isn't it B or D?Exactly. The third one is NOT an isomer. Isomers have different structural arrangement but same formula.
All other options are isomers since they have the same formula but different structures. While the third one is NOT an isomer, since it has the same structural arrangement.
But why isn't it B or D?
B and D have a different structure. They are branched. Isomers have to have a branched structure. And all other options are branched. Which means they are isomers.
Oh alright, thanks for the explanationExactly. The third one is NOT an isomer. Isomers have different structural arrangement but same formula.
All other options are isomers since they have the same formula but different structures. While the third one is NOT an isomer, since it has the same structural arrangement.
I know I am asking how can light pass if it is smoked or whateverOf course glass cannot be frozen. It's just a layer of condensed smoke or something on it. This might be for magnification. See page 214 of Federal Physics.
got itOf course glass cannot be frozen. It's just a layer of condensed smoke or something on it. This might be for magnification. See page 214 of Federal Physics.
A better explanation would be that the last CH3 is still attached to the second last CH2 making it pentane-1 or something like that.In the other it is attached toBut why isn't it B or D?
Actually its'a bit confusing to determine the isomers in condensed structural formula. So make the complete structural formula first showing all bonds. Then see the CH3 group is attached to the first carbon atom. In the first and secondoption, the CH3 group is attached to the second carbon atom, in the last option it's attached to the 3rd carbon atom.
in this case the limiting reactant is oxygen... since 1 mole of n2 will react will 2 mole of o2... so if n2 is increaased still the same energy will be released as the o2 is still 1 mole...Another question
View attachment 39864
Since the no. of moles are changing, won't the enthalphy change also change?
Alright, thanksin this case the limiting reactant is oxygen... since 1 mole of n2 will react will 2 mole of o2... so if n2 is increaased still the same energy will be released as the o2 is still 1 mole...
haha look at out pics ... they r in the same pose...(but mine is cooler)Alright, thanks
Ik thankstake a fresh leaf and put it in water ..... bubbles will appear ..showing the presence of stomata
huhIk thanks
No, it won't be. Is is limited by the amount of oxygen.Another question
View attachment 39864
Since the no. of moles are changing, won't the enthalphy change also change?
A better experiment would be to attach pieces of cobalt chloride paper to both ends of the leaf.Lower end would change color to pink and indicate presence of stomataHow can we demonstrate presence of stomata in the leaves?
Isn't that for proving that transpiration occurs most at the bottom of the leaf?A better experiment would be to attach pieces of cobalt chloride paper to both ends of the leaf.Lower end would change color to pink and indicate presence of stomata
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