Biology; Chemistry; Physics: Post your doubts here!

[kirann]

1) Find Total Mr of Formula
2) Find Mr of Salt
3) Subtract Salt Mr from Total
4) Divide the number you get by 18 (Mr of Water)

ok

 

[Ram97]

1) Find Total Mr of Formula
2) Find Mr of Salt
3) Subtract Salt Mr from Total
4) Divide the number you get by 18 (Mr of Water)

Can u give an example??

 

[FLRNAB]

It is an oxidizing acid, according to wikipedia.

Apparently, Oxidizing acids can react with metals that are less reactive.
Like Dilute Nitric Acid, the Nitrate Ions act as the oxidizing agents.

In Concentrated Sulphuric acid, the Sulfate ions act as oxidizing agent, and can even reduce copper to Cu+2.

But why don't Gold and Platinum react? Is it something to do with their metallic bonding?

Copper is a metal too, yet is reacts.

Intuition:
Jitna sust bnda utna mushkil usko kaam py lgana. Platinum sab sy sust, Gold us say kam aur copper us say bhi kam.
Kaam py lgana ky liye danda chahiye. Ziyada sust ky liye sakht danda aur kam sust ky lie normal danda.

So you need Concentration if you want to react with these metals. All metals will react but you need different acid.

I replied to your statement of Gold reacting with normal nitric acid not concentrated.

 

[FLRNAB]

Can u give an example??

CuSO4.xH2O

Total = 250
Mr of CuSO4 = 160
Mr of Water present = 250 - 160 = 90
x = 90 / 18 = 5

 

[peacce]

CuSO4.xH2O

Total = 250
Mr of CuSO4 = 160
Mr of Water present = 250 - 160 = 90
x = 90 / 18 = 5

how come the tota l is 250????

 

[peacce]

FLRNAB

 

[princess Anu]

When dilute sulfuric acid is electrolysed between inert electrodes, which statements are correct?
1 Hydrogen is released at the negative electrode.
2 Oxygen is released at the positive electrode.
3 Sulfur dioxide is released at the positive electrode. 4 The acid becomes more concentrated.
A 1, 2 and 4 B 1 and 2 only C 2 and 3 D 3 and 4

 

[Ram97]

When dilute sulfuric acid is electrolysed between inert electrodes, which statements are correct?
1 Hydrogen is released at the negative electrode.
2 Oxygen is released at the positive electrode.
3 Sulfur dioxide is released at the positive electrode. 4 The acid becomes more concentrated.
A 1, 2 and 4 B 1 and 2 only C 2 and 3 D 3 and 4

B

 

[kirann]

why does'nt copper react with dilute sulphuric acid?
how come you ppl deduce which metal can react with which acid

 

[Ram97]

why does'nt copper react with dilute sulphuric acid?
how come you ppl deduce which metal can react with which acid

Copper is less reactive than Hydrogen
It all depends on the Reactivity Series. The more reactive metal displaces the less reactive metal
E.g: Sodium + Calcium Hydroxide = Sodium Hydroxide + Calcium

 

[Abdul Hanan]

why does'nt copper react with dilute sulphuric acid?
how come you ppl deduce which metal can react with which acid

K,Na,Li,Ca,Mg,Al,Zn,Fe,Pb..... react with dilute acids.
Cu,Hg,Ag,Au,Pt...... do not react with dilute acids...

 

[kirann]

K,Na,Li,Ca,Mg,Al,Zn,Fe,Pb..... react with dilute acids.
Cu,Hg,Ag,Au,Pt...... do not react with dilute acids...

thanks

 

[Alyjohn]

Part 3 please explain anyone??

 

[kirann]

Part 3 please explain anyone??

formula for molarity is
molarity=moles/vol
molarity= 0.100 mol/dm^3
vol=44 cm^3
1 cm^3=1000 dm^3
so,
0.100=mole/44
0.100*44/1000=moles
moles=0.0044 moles (ans)

 

[Ram97]

Part 3 please explain anyone??

Its simple.
You know the volume. Moles can be calculated by the formula
moles = conc./1000 x volume
moles = 0.100/1000 x 44
moles = 0.0044

 

[Ram97]

formula for molarity is
molarity=moles/vol
molarity= 0.100 mol/dm^3
vol=44 cm^3
1 cm^3=1000 dm^3
so,
0.100=mole/44
0.100*44/1000=moles
moles=0.0044 moles (ans)

Use the formula which I mentioned its more simple

 

[Alyjohn]

formula for molarity is
molarity=moles/vol
molarity= 0.100 mol/dm^3
vol=44 cm^3
1 cm^3=1000 dm^3
so,
0.100=mole/44
0.100*44/1000=moles
moles=0.0044 moles (ans)

Thank you

 

[Alyjohn]

Its simple.
You know the volume. Moles can be calculated by the formula
moles = conc./1000 x volume
moles = 0.100/1000 x 44
moles = 0.0044

Thanks bro

 

[kirann]

Use the formula which I mentioned its more simple

whats the difference

 

[Ram97]

whats the difference

Not much!! But in ur formula u convert it into dm^3 to solve further. But here u need to put in the values and voila!!