*Biology Paper 5 tips*

[Xainab]

yes

Ok, thank youuu! Means alot

 

[magnesium]

result of t test is opposite of chi squared test?

 

[magnesium]

Ok, thank youuu! Means alot

result of t test is opposite of chi squared test?

 

[waver525]

pls can any one explain how the confidence levels are calculated for q2 part b iv?
http://papers.xtremepapers.com/CIE/...and AS Level/Biology (9700)/9700_w08_qp_5.pdf
http://papers.xtremepapers.com/CIE/...and AS Level/Biology (9700)/9700_w08_ms_5.pdf

 

[magnesium]

i mean that if chi square value lies to the left of critical value....we say that difference is not significant.....so if t value lies to the left , is the conclusion same...???????

 

[waver525]

result of t test is opposite of chi squared test?

no they both are same..... t value greater than critcal value or p leess than 0.05 thn null hypo is increct

 

[glowinthedarkhamster]

thank you!

 

[Just visiting]

yes

why?

 

[magnesium]

why?

i dnt know the reason but read some where

 

[klaus23]

thnx..this helps alot...goodluck to u all

 

[Ineedhelp]

yes

what are those?

 

[magnesium]

what are those?

do u take physics?

 

[Ineedhelp]

do u take physics?

no bio and chem.

 

[Just visiting]

i dnt know the reason but read some where

but if u check o/n 10 53 u see that bar chart has +- of standard deviation and not x2

 

[magnesium]

no bio and chem.

​

P5.JPG

 

[PhyZac]

but if u check o/n 10 53 u see that bar chart has +- of standard deviation and not x2

Error bars, are not made using the standard deviation value, directly.

It is +/- 2 x standard error.

Standard error is standard deviation divided by root of n.

n is number of values.

 

[Ineedhelp]

Ohh.

P5.JPG

isn't that the standard deviation? showing how it disperses about the mean? (+/-)

 

[Xainab]

but if u check o/n 10 53 u see that bar chart has +- of standard deviation and not x2

For standard deviation, its the same. For standard error, you multiply by 2

 

[Ineedhelp]

to find the value of X^2 for the chi squared test.. you add up all the (O-E)^2 / E values and divide it by what? n+1?

 

[Just visiting]

For standard deviation, its the same. For standard error, you multiply by 2

aaaa so if its standard error you ,multiply by root n
ok thanks