Hello,,can anyone help me with this please ,,
CH4 + 2O2 → CO2 + 2H2O
Energy needed to break bonds: 4 (C-H): 435 x 4 = 1740 KJ/Mol 2 (O=O): 497 x 1 = 994 KJ/Mol Total energy in: 1740 + 994 = 2734 KJ/Mol Energy needed to form bonds: 2 (C=O): 803 x 2 = 1606 KJ/Mol 4 (H-O): 464 x 4 = 1856 KJ/Mol Total energy out: 1606 + 1856 = 3462 KJ/Mol ΔH= 2734 – 3462 = -728 KJ/Mol r Therefore reaction is Exothermic
Now my question is ,,why didnt we time 2O2 by 4 like we did with CH4 ? does this mean that we only consider the number on the right hand side only ? if yes,, then why did we time 2H2O by 4 :/
thanks..
CH4 + 2O2 → CO2 + 2H2O
Energy needed to break bonds: 4 (C-H): 435 x 4 = 1740 KJ/Mol 2 (O=O): 497 x 1 = 994 KJ/Mol Total energy in: 1740 + 994 = 2734 KJ/Mol Energy needed to form bonds: 2 (C=O): 803 x 2 = 1606 KJ/Mol 4 (H-O): 464 x 4 = 1856 KJ/Mol Total energy out: 1606 + 1856 = 3462 KJ/Mol ΔH= 2734 – 3462 = -728 KJ/Mol r Therefore reaction is Exothermic
Now my question is ,,why didnt we time 2O2 by 4 like we did with CH4 ? does this mean that we only consider the number on the right hand side only ? if yes,, then why did we time 2H2O by 4 :/
thanks..