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Two reactions and their enthalpy changes are shown.
2C(s) + 2H2(g) → C2H4(g) ∆Ho = +52.2 kJ mol–1
C2H2(g) + H2(g) → C2H4(g) ∆Ho = –175.8 kJ mol–1
These data can be used to calculate the enthalpy change for the reaction shown.
2C(s) + H2(g) → C2H2(g) ∆Ho= X
What is the value of X?
A –228.0 kJ mol–1
B –123.6 kJ mol–1
C +123.6 kJ mol–1
D +228.0 kJ mol–1
I need the full method please...(THE ANSWER IS D)
2C(s) + 2H2(g) → C2H4(g) ∆Ho = +52.2 kJ mol–1
C2H2(g) + H2(g) → C2H4(g) ∆Ho = –175.8 kJ mol–1
These data can be used to calculate the enthalpy change for the reaction shown.
2C(s) + H2(g) → C2H2(g) ∆Ho= X
What is the value of X?
A –228.0 kJ mol–1
B –123.6 kJ mol–1
C +123.6 kJ mol–1
D +228.0 kJ mol–1
I need the full method please...(THE ANSWER IS D)
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