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Hey, did you people gave 21, 22 or 23. Which paper had this K.C question (0.44 answr) and the rest.
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m2rulz143 said:Guys the answer to kc was 0.429 or 0.43 coz after rxn with naoh 0.06 moles of acid will be left and then at the equillibrium half of it will react so 0.03 moles will be there at equillibrium and the table will be something like this
Acid: 0.03 alcohol: 0.07(coz 0.03 reacted to form ester and water) ester 0.03 ( 1:1 ratio) and water 0.03. For those of you sayin 0.06 mol acid at equillibrium this is not possible that ester is being formed without acid being used up. I hope im pretty clear on this..
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