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1 cannot be as molecules have to join. The molecules can join in any fashion so it can be any number less than 1.
thanks
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1 cannot be as molecules have to join. The molecules can join in any fashion so it can be any number less than 1.
yes B thanksv=f*lambda
speed of light divided by wavelength of uv waves
(3*10^8)/ (1*10^-7) = 3*10^15
is B the ans??
thia question drove me crazy and the answer was so simple.
Thank you mehranshaikh
After about 40 minutes of scribbling, I've concluded to the answer.
First residue: CH3(CH2)4CH=CHCH2CH=CH(CH2)7CO2
Second residue: CH3(CH2)7CH=CH(CH2)7CO2
Original branch: CH3(CH2)3CH=CHCH=CHCH=CH(CH2)7CO2
First, I omitted out the unchanged part of molecules resulting in:
First residue: (CH2)4...CHCH2CH...
Second residue: (CH2)7...
For first residue: [Looking at the breaking of double bonds]
One CH2 molecule broke up and moved to change (CH2)3 to (CH2)4. Hence this part is justified.
=CHCH=CHCH= (Break the middle double bond by adding 1 hydrogen atom on each carbon). [Total 2 Hydrogen atoms.]
This results in: =CHCH2CH2CH=
Take one CH2 away since it was already added to (CH2)3
Result: =CHCH2CH=
For second residue: [The end part remains same, so we look at breaking the double bonds again.]
-CH=CHCH=CHCH= (Break the first two double bonds by adding 2 Hydrogen atoms on each carbon.) [Total 4 Hydrogen atoms].
-CH2CH2CH2CH2CH= (Take three CH2 molecules to original (CH2)3 making it (CH2)7 again justifying this part.)
Therefore the first residue required 1 mole of Hydrogen and second required 2 moles. However, the second residue is formed with 2 branches hence it multiply the moles by 2, giving us 1 Mole + 2 Moles + 2 Moles = 5.
5 Moles of Hydrogen is required, which is (B).
P1 O/N 2003 chemistry ...ques 15 please?
thnx in advance!
since the C:H ratio is high, we can predict that benzene is present.
Since it is not readily oxidised by mild oxidising agents, we say that it is a tertiary alcohol. draw the structures and the only compound which produced by the dehydration of X is D.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s08_qp_1.pdf
FOR THIS PAPER NUMBER-25 HOW IS THE ANSWER (c) its written in the book that for secondary halogen hylides both sn1 and sn2 happens but question ass for ONLY BY AN SN1 MECHANICSM please help
thanks
The answer is D, not C.
D is a tertiary haloganoalkane. C is a secondary haloganoalkane.
D can ONLY follow Sn1 mechanism, whereas C can follow both Sn1 and Sn2 mechanism.
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