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help needed in nov 2002 q 35 and mj 02 q 28 plzzz! ?
i have a big problem in resolving the vectors and finding the resultant and all . mainly in mechanic i need help .you can post your doubts anytime. I believed all of us here are willing to help.
i have a big problem in resolving the vectors and finding the resultant and all . mainly in mechanic i need help .
lol physics not chem ... thanks anywayCouldnt find the Mj paper.
The answer for the Oct-nov 02 question is:
Option 1 is correct as bond length increase down the group and so the dissociation increases and bond energy increases.
Option 2, I am unsure about it :\
Option 3 is also correct as trend in reduction increases down the group
I think the answer is A
lol physics not chem ... thanks anyway
help needed in nov 2002 q 35 and mj 02 q 28 plzzz! physicssss syed1995 ?
You'll find this video helpful, hopefully:.
Physics:
Oct/Nov'11 Paper 11. Question: 12,20,24,26,27,28,29,30.
Please explain these questions to me as I didnt understand even after seeing the mark scheme. I know I have problem in my concept. Can anyone please help me out?
ans. is B ie 1&2 ..but how
when CL reacts with mg it forms MgCl2 and when it reacts with Na , NaCl is formed so the number of moles reacting with X which is Mg is twice the number of moles reacting with Y which is Na
but i dont how it applies to H2 and kBr
same doubt
Mg + Cl2 -> MgCl and 2Na + Cl2 -> 2NaCl,im trying to slove . but the moles of Cl reacting with H2 and Kbr are the same . its so confusing .
Mg + Cl2 -> MgCl and 2Na + Cl2 -> 2NaCl,
H2 + Cl2 -> 2HCl and Cl2 + 2KBr -> 2KCl + Br2 ??
Mg + Cl2 -> MgCl and 2Na + Cl2 -> 2NaCl,
H2 + Cl2 -> 2HCl and Cl2 + 2KBr -> 2KCl + Br2 ??
june 07 mcq 36 plzzzz35 D...
cuz if the resistance of Variable resistor is increased.. It will have more PD dropped on the resistor and less PD on the wire.
And Zero deflection occurs when The PD across both points is zero (SAME PD means no current flows).. so that means we have to increase the resistance of the wire.. for that we would have to move the pointer further towards Y. And it will be nearer to Y.
MJ 02 Q28
The signal is decreasing meaning it's going towards a dark fringe. And for dark fringe path difference needs to be Lambda/2 .. and Path difference = the distance from one fringe - distance from other fringe..
S2 Distance - S1 distance = Lambda/2
so the answer according to me would be C.
Let me know if the answers are correct.. and if you got the explanation .. since I have the unsolved past papers with no MS.
june 07 mcq 36 plzzzz
ans. is B ie 1&2 ..but how
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