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Chemistry MCQ thread...

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Which sodium salts form a precipitate when AgNO3(aq) followed by dilute NH3(aq) is added to its
aqueous solution?

1 chloride

2 bromide

3 iodide
 
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286
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4
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0
At a total pressure of 1.0 atm, dinitrogen tetraoxide is 50 % dissociated at a temperature of 60 C,
according to the following equation.
N2O4--> 2NO2
What is the value of the equilibrium constant, Kp, for this reaction at 60 C?
A 1/3 atm B 2/3 atm C 4/3 atm D 2 atm
how to solve this question ? :%)
 
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113
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1 mol of sodium bromate reacts with 3 mol of hydroxylamine according to the data given..
the equation shows that bromate takes 6 mol of electrons to reduce itself so these electrons come from hydroxyl amine....3 mol of hydroxylamine giv 6 mol of electron so 1 mol will give 2 mol of electrons....
In giving 2 mols of electron...the oxidation number of nitrogen must increase by 2....
in hydroxyl amine the oxid number of nitrogen is -1 so by giving 2 mol of electrons the oxid number increases by 2
The new oxid number shld be +1...Only option C N2O shows this so C i corrct
 
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xHazeMx said:
Which sodium salts form a precipitate when AgNO3(aq) followed by dilute NH3(aq) is added to its
aqueous solution?

1 chloride

2 bromide

3 iodide




Its C rite???


Hateexams93 said:
At a total pressure of 1.0 atm, dinitrogen tetraoxide is 50 % dissociated at a temperature of 60 C,
according to the following equation.
N2O4--> 2NO2
What is the value of the equilibrium constant, Kp, for this reaction at 60 C?
A 1/3 atm B 2/3 atm C 4/3 atm D 2 atm
how to solve this question ? :%)



I was also goin to ask the same Q!!!
 
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426
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farrukh said:
1 mol of sodium bromate reacts with 3 mol of hydroxylamine according to the data given..
the equation shows that bromate takes 6 mol of electrons to reduce itself so these electrons come from hydroxyl amine....3 mol of hydroxylamine giv 6 mol of electron so 1 mol will give 2 mol of electrons....
In giving 2 mols of electron...the oxidation number of nitrogen must increase by 2....
in hydroxyl amine the oxid number of nitrogen is -1 so by giving 2 mol of electrons the oxid number increases by 2
The new oxid number shld be +1...Only option C N2O shows this so C i corrct
that was brilliant !!!
 
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hassam said:
zishi......???

Okay, so it goes like this:

Changing the volumes and concentrations gives us moles of Nitrogen compound and bromine one:

NaBrO3 : Nh2OH
4x10^-4 : 1.2x10^-3
1 : x

x= 3

As one bromine atom gains 6 electrons. So each of Nitrogen atoms will loose 2 electrons.

In Nh2OH its oxidation state is -1, so by gaining two electrons its oxidation stat changes to +1. And Only N2O has oxidation state of nitrogen as +1.

xHazeMx said:
Which sodium salts form a precipitate when AgNO3(aq) followed by dilute NH3(aq) is added to its
aqueous solution?

1 chloride

2 bromide

3 iodide


2 and 3.

Hateexams93 said:
At a total pressure of 1.0 atm, dinitrogen tetraoxide is 50 % dissociated at a temperature of 60 C,
according to the following equation.
N2O4--> 2NO2
What is the value of the equilibrium constant, Kp, for this reaction at 60 C?
A 1/3 atm B 2/3 atm C 4/3 atm D 2 atm
how to solve this question ? :%)

Consider moles of N2O4 as 1 and that of NO2 as zero.

50% of N2O4 dissociates means that 1 moles of NO2 is formed. So total number of moles = 1.5

PArtial pressure of N2O4 = 0.5/1.5 = 1/3
Partial pressure of NO2= 1/1.5 = 2/3

So Kp = (2/3)^2 divided by (1/3). So 4/3 is the answer.
 
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Its Q related to salt analysis.....

when AgNO3 is added to a solution containing halide ion there is always a precipitate!!!

On adding aq. NH3 the precipitate in solution containing Chloride ion, dissolves!!!

In bromide case, it is partially soluble!!

And in iodide, its insoluble so C is the rite ans!!! :D
 
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farrukh said:
1 mol of sodium bromate reacts with 3 mol of hydroxylamine according to the data given..
the equation shows that bromate takes 6 mol of electrons to reduce itself so these electrons come from hydroxyl amine....3 mol of hydroxylamine giv 6 mol of electron so 1 mol will give 2 mol of electrons....
In giving 2 mols of electron...the oxidation number of nitrogen must increase by 2....
in hydroxyl amine the oxid number of nitrogen is -1 so by giving 2 mol of electrons the oxid number increases by 2
The new oxid number shld be +1...Only option C N2O shows this so C i corrct



I also thought the same but wasn't sure!!! :D
 
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Someone pls answer...

Q. HCN adds to ketones...the table shows the relative rates of reactions under diff conditions

CONDITION ---------- RELATIVE RATE
aqueous solution --------- slow
acidified solution -------- virtually zero
alkaline solution --------- very rapid

Which is likely to be involved in the rate determining step of the reaction...

A. Cyanide ion
B. Hydroxide ion
C. H+ ion
D. HCN
E. H2O
 
Messages
772
Reaction score
149
Points
38
farrukh said:
Someone pls answer...

Q. HCN adds to ketones...the table shows the relative rates of reactions under diff conditions

CONDITION RELATIVE RATE
aqueous solution slow
acidified solution virtually zero
alkaline solution very rapid

Which is likely to be involved in the rate determining step of the reaction...

A. Cyanide ion
B. Hydroxide ion
C. H+ ion
D. HCN
E. H2O

I'm not an A2 student, but I guess I may answer it. The answer has to be A(maybe). BUT according to the given conidtions, E may also be the answer.
 
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113
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3
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28
Q. Which of the following will not decolorize aqueous bromine?

A. Chlorine gas
B. ethene gas
C. FeSO4 aq
D. phenol aq.
E ethanal (liquid)
 
Messages
772
Reaction score
149
Points
38
farrukh said:
Q. Which of the following will not decolorize aqueous bromine?

A. Chlorine gas
B. ethene gas
C. FeSO4 aq
D. phenol aq.
E ethanal (liquid)

I guess ethanal. Again, phenols are in A2.
 
Messages
113
Reaction score
3
Points
28
Zishi said:
farrukh said:
Someone pls answer...

Q. HCN adds to ketones...the table shows the relative rates of reactions under diff conditions

CONDITION RELATIVE RATE
aqueous solution slow
acidified solution virtually zero
alkaline solution very rapid

Which is likely to be involved in the rate determining step of the reaction...

A. Cyanide ion
B. Hydroxide ion
C. H+ ion
D. HCN
E. H2O

I'm not an A2 student, but I guess I may answer it. The answer has to be A(maybe). BUT according to the given conidtions, E may also be the answer.
you got it correct ...A is the answer...i ws nt sure whether its an as question or a2
 
Messages
113
Reaction score
3
Points
28
Zishi said:
farrukh said:
Q. Which of the following will not decolorize aqueous bromine?

A. Chlorine gas
B. ethene gas
C. FeSO4 aq
D. phenol aq.
E ethanal (liquid)

I guess ethanal. Again, phenols are in A2.
The answer given in book is chlorine gas
 
Messages
772
Reaction score
149
Points
38
farrukh said:
Zishi said:
farrukh said:
Someone pls answer...

Q. HCN adds to ketones...the table shows the relative rates of reactions under diff conditions

CONDITION RELATIVE RATE
aqueous solution slow
acidified solution virtually zero
alkaline solution very rapid

Which is likely to be involved in the rate determining step of the reaction...

A. Cyanide ion
B. Hydroxide ion
C. H+ ion
D. HCN
E. H2O

I'm not an A2 student, but I guess I may answer it. The answer has to be A(maybe). BUT according to the given conidtions, E may also be the answer.
you got it correct ...A is the answer...i ws nt sure whether its an as question or a2

Well, WOW! I didn't know that my AS concepts may solve A2 questions. :Yahoo!: Well, as far as I know, the rate determining step is the slowest step of the reaction. That is the step in which cyanide ions attack the carbonyl group carbon atom.
 
Messages
113
Reaction score
3
Points
28
Q. Which of the following are true for conc sulfuric acid

1. ito oxidizes ethanoic acid
2. it dehydrates methanoic acid
3. it is reduced by potassium iodide

Well, WOW! I didn't know that my AS concepts may solve A2 questions. Well, as far as I know, the rate determining step is the slowest step of the reaction. That is the step in which cyanide ions attack the carbonyl group carbon atom.

way to go :good:
 
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426
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farrukh said:
Q. Which of the following are true for conc sulfuric acid

1. ito oxidizes ethanoic acid
2. it dehydrates methanoic acid
3. it is reduced by potassium iodide

Well, WOW! I didn't know that my AS concepts may solve A2 questions. Well, as far as I know, the rate determining step is the slowest step of the reaction. That is the step in which cyanide ions attack the carbonyl group carbon atom.

way to go :good:
is that an AS question ? :D
 
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