- Messages
- 70
- Reaction score
- 23
- Points
- 18
1) The use of the Data Booklet is relevant to this question.
What is the number of molecules in 500 cm3 of oxygen under room conditions?
A) Step 1: Under room conditions 1 mol of oxygen occupies 24 dm3
x mol of oxygen occupies 0.500 dm3
Amount of oxygen = (0.500 x 1) / 24 = 0.0208 mol
Step 2: There are 6.02 x 1023 molecules in 1 mol of oxygen
There are "y" molecules in 0.0208 mol of oxygen
Number of oxygen molecules = [0.0208 x (6.02 x 1023)] / 1 = 1.25 x 1022
2) In the preparation of soft margarine, glyceryl trieleostearate
is suitably hydrogenated so that, on average, one of its side-chains is converted into the CH3(CH2)4CH=CHCH2CH=CH(CH2)7CO2 residue and two side-chains are converted into the
CH3(CH2)7CH=CH(CH2)7CO2 residue.
How many moles of hydrogen are required to convert one mole of glyceryl trieleostearate into the soft margarine?
B) Step 1: Count the hydrogen atoms in the side-chains.
Upper side-chain and lower side-chain: 2 x (3+6+6+14) = 58
Middle side-chain: 3 + 6 + 6 + 14 = 29
Step 2: Count the hydrogen atoms in each residue
First residue: 3 + 8 + 6 + 14 = 31
Second residue x 2 (because two side-chains are converted): 2 x (3 + 14 + 2 + 14) = 66
Step 3: Calculate how many hydrogen atoms had to be added to each side-chain in order to form the residues.
Upper and lower side-chain residues have 66 - 58 extra hydrogens = 8 extra hydrogens
Middle side-chain residue has 31-29 extra hydrogens = 2 extra hydrogens
Step 4: You know that 10 hydrogen atoms have been added to the original molecule. Each hydrogen molecule contains two hydrogen atoms, so there are 10/2 = 5 hydrogen molecules ie. 5 moles of hydrogen
3) Which isotope of an element in the third period of the Periodic Table contains the same number of neutrons as 3216S?
D) Number of neutrons = relative atomic mass - atomic number (protons)
Neutrons in an atom of S = 32 - 16 = 16
Neutrons in an atom of P = 31 - 15 = 16
3115P
4) The successive ionisation energies, in kJ mol-1 of an element X are given below.
870 1800 3000 3600 5800 7000 13200
What is X?
C) Arsenic and Zirconium have a small number of protons compared to Tellerium and Iodine. Their number of protons is not big enough to be consistent with the high 7th ionization energy.
You're left with either Tellerium or Iodine. You can see the ionization energies of iodine in the Data Booklet, and they're not consistent with the ionization energies above, therefore the answer is Tellerium
5) Which of the following solids has a simple molecular lattice?
D) Magnesium Oxide has a a giant ionic lattice.
Sodium has a metallic structure
Silicon (IV) Oxide has a giant covalent structure
The only chemical with a simple molecular lattice is sulphur
What is the number of molecules in 500 cm3 of oxygen under room conditions?
A) Step 1: Under room conditions 1 mol of oxygen occupies 24 dm3
x mol of oxygen occupies 0.500 dm3
Amount of oxygen = (0.500 x 1) / 24 = 0.0208 mol
Step 2: There are 6.02 x 1023 molecules in 1 mol of oxygen
There are "y" molecules in 0.0208 mol of oxygen
Number of oxygen molecules = [0.0208 x (6.02 x 1023)] / 1 = 1.25 x 1022
2) In the preparation of soft margarine, glyceryl trieleostearate
is suitably hydrogenated so that, on average, one of its side-chains is converted into the CH3(CH2)4CH=CHCH2CH=CH(CH2)7CO2 residue and two side-chains are converted into the
CH3(CH2)7CH=CH(CH2)7CO2 residue.
How many moles of hydrogen are required to convert one mole of glyceryl trieleostearate into the soft margarine?
B) Step 1: Count the hydrogen atoms in the side-chains.
Upper side-chain and lower side-chain: 2 x (3+6+6+14) = 58
Middle side-chain: 3 + 6 + 6 + 14 = 29
Step 2: Count the hydrogen atoms in each residue
First residue: 3 + 8 + 6 + 14 = 31
Second residue x 2 (because two side-chains are converted): 2 x (3 + 14 + 2 + 14) = 66
Step 3: Calculate how many hydrogen atoms had to be added to each side-chain in order to form the residues.
Upper and lower side-chain residues have 66 - 58 extra hydrogens = 8 extra hydrogens
Middle side-chain residue has 31-29 extra hydrogens = 2 extra hydrogens
Step 4: You know that 10 hydrogen atoms have been added to the original molecule. Each hydrogen molecule contains two hydrogen atoms, so there are 10/2 = 5 hydrogen molecules ie. 5 moles of hydrogen
3) Which isotope of an element in the third period of the Periodic Table contains the same number of neutrons as 3216S?
D) Number of neutrons = relative atomic mass - atomic number (protons)
Neutrons in an atom of S = 32 - 16 = 16
Neutrons in an atom of P = 31 - 15 = 16
3115P
4) The successive ionisation energies, in kJ mol-1 of an element X are given below.
870 1800 3000 3600 5800 7000 13200
What is X?
C) Arsenic and Zirconium have a small number of protons compared to Tellerium and Iodine. Their number of protons is not big enough to be consistent with the high 7th ionization energy.
You're left with either Tellerium or Iodine. You can see the ionization energies of iodine in the Data Booklet, and they're not consistent with the ionization energies above, therefore the answer is Tellerium
5) Which of the following solids has a simple molecular lattice?
D) Magnesium Oxide has a a giant ionic lattice.
Sodium has a metallic structure
Silicon (IV) Oxide has a giant covalent structure
The only chemical with a simple molecular lattice is sulphur