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Chemistry P31

Messages
255
Reaction score
85
Points
38
true but i think both do actually
A gets rusted, and so smaller
B loses electrons as it gives them to A
in book it is mentioned rusting is a redox reaction
oxidation strictly happens on B
actually as B loses electron the ion dissolves and the mass of B decreases
rust settles on the A increasing its mass as its discharged

formula was Al2O3.2H2O
 
Messages
531
Reaction score
96
Points
28
its definitly A since fe(ii) is oxidized to fe(iii) (rust) thought bubbling O2 gas :p

No because The electrons flow from the cathode(B) to the anode(A) therefore, the Fe in the cathode is going out as ions Fe3+ and releasing electons....the Fe3+ then reacts and forms Fe2O3....
I think this is right....coz thats how I learnt it in school....but Im not entirely sure that its B....
 
Messages
26
Reaction score
5
Points
3
Guyzz i wrote it FeO2.H2O because i got the mole ratio 1:2:1 - what do u think?
 
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