Chemistry P52

[Ms.qureshi]

Can anyone help me in Q1.part (d) w09 52..
Pllzzz

 

[Mr.Smart]

No. you'll use a pyrex tube.

explain the procedure with your diagram please !!

 

[saifookhan]

Is it okay if I link other members to your answer on this thread? A lot of people seem to be asking about this

Sure. Spread the knowledge.

 

[saifookhan]

explain the procedure with your diagram please !!

MnO4 + HCL will produce H2.
H2 will go in the pyrex tube and react with the lead oxide.
The excess H2 is burnt off.
This also decreases the probability of tube bursting.

Pray for my good result.
Thanks.

 

[saifookhan]

Can anyone help me in Q1.part (d) w09 52..
Pllzzz

The key here is 'monobasic'and 'dibasic' acids.

Mono basic = 1H+
Dibasic = 2H+

So in the table, the volume will be same i.e. 25.0 cm^3
The concs will be 2, 1, 2, 2, 1 respectively.

 

[Mr.Smart]

MnO4 + HCL will produce H2.
H2 will go in the pyrex tube and react with the lead oxide.
The excess H2 is burnt off.
This also decreases the probability of tube bursting.

Pray for my good result.
Thanks.

to yarr jo Oxygen produce ho rhi hai reduction say, wo kahan jaye gi? :O

 

[saifookhan]

to yarr jo Oxygen produce ho rhi hai reduction say, wo kahan jaye gi? :O

PbO + H2 -> Pb + H2O.

 

[Mr.Smart]

PbO + H2 -> Pb + H2O.

ohh got it now
thanks a lot
ab j12 , qp 52 , k question ki drawing bhe smjhao

 

[saifookhan]

ohh got it now
thanks a lot
ab j12 , qp 52 , k question ki drawing bhe smjhao

Bas kar bhai. Mujhay bhi parhnay day.

MnO4 + HCL will produce H2.
H2 will go in the pyrex tube and react with the lead oxide.
The excess H2 is burnt off.
This also decreases the probability of tube bursting.

 

[Mr.Smart]

Bas kar bhai. Mujhay bhi parhnay day.

MnO4 + HCL will produce H2.
H2 will go in the pyrex tube and react with the lead oxide.
The excess H2 is burnt off.
This also decreases the probability of tube bursting.

yar drawings confusing hain :/

 

[saifookhan]

yar drawings confusing hain :/

Kia samajh nahi aa raha ?

 

[Apter_95]

Can anyone draw the answer for 1.c) of paper 52 M/J 2012??

I don't know what to use ...

And how to collect nitrogen oxide while collecting water vapour by using liebig condenser???

 

[Mr.Smart]

Kia samajh nahi aa raha ?

j12, qp 52, q1 c

 

[saifookhan]

Can anyone draw the answer for 1.c) of paper 52 M/J 2012??

I don't know what to use ...

And how to collect nitrogen oxide while collecting water vapour by using liebig condenser???

I'm stuck on that one too. Damn difficult question.

 

[saifookhan]

j12, qp 52, q1 c

btaya tou.
MnO4 oxidizing agent hai.
HCl acid hai. Donon mil k salt + H2 banayaingay.
H2 uper chali jayegi.
Aur wahan ja k react karaigi..

Jo bach jayegi usko bori main band kar k jala daingay.

 

[Apter_95]

I'm stuck on that one too. Damn difficult question.

I feel like im gonna fail in paper 5 ....

 

[saifookhan]

I feel like im gonna fail in paper 5 ....

Don't let yourself down.
Whatever came last year won't come now. Stay positive.

 

[Ms.qureshi]

The key here is 'monobasic'and 'dibasic' acids.

Mono basic = 1H+
Dibasic = 2H+

So in the table, the volume will be same i.e. 25.0 cm^3
The concs will be 2, 1, 2, 2, 1 respectively.

Thanks alot..
Best of luck for tomorrow

 

[Resha rimaz]

wat tym is ur ppr guyz. I mean how many hours more?

 

[Ujjwal Basnet]

I would suggest that u solve some of the papers and compare it with the mark schemes . u can also see some solved p5 .if u need them ,pm me ur email address , i'll send them to u! (they r solved by me)

[email protected]...can u plz send them to me