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Chemistry Paper 4-theory- doubts =D

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I think it's like this- so in K the reaction is basically the first one right? RCH3 -> RCH2Cl. But you'll notice in the product, there's actually 9 places that Cl could have been put in. It can replace all the hydrogens in the methyl groups. So it becomes 1x9, and the ratio is 21:9.
seems legit :p
 
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I think it's like this- so in K the reaction is basically the first one right? RCH3 -> RCH2Cl. But you'll notice in the product, there's actually 9 places that Cl could have been put in. It can replace all the hydrogens in the methyl groups. So it becomes 1x9, and the ratio is 21:9.
If that didn't make sense count the number of hydrogens- it's 9. There's 9 places that the Cl could have been put in so it's 1x9. Hope this helps!
 
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ON12 no.7bii wudnt it be suspect 1 because u c his fingerprints were found in both crime scenes!!! I just donot get y ms says suspect 2!! N they didn’t give valid reason 2!!! Btwn if its suspecvt 2 then his finger print ws only found in scene 1 not scene 2!!!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w12_qp_42.pdf

Any 1 any idea!! Thank u!!!
lol yeah i spent like 30 mins on this question figuring out why the mark scheme is saying the complete opposite and at the end i dont know why..i bet the examiner is a foolish inspector so he doesn't know these kind of stuff :p
 
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ON12 no.7bii wudnt it be suspect 1 because u c his fingerprints were found in both crime scenes!!! I just donot get y ms says suspect 2!! N they didn’t give valid reason 2!!! Btwn if its suspecvt 2 then his finger print ws only found in scene 1 not scene 2!!!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w12_qp_42.pdf

Any 1 any idea!! Thank u!!!
I got it as suspect when i solved...i dont know why..but it as similar the crime scene 1..
i know this isnt useful...
 
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PLEASE ANYONE SOLVE THIS QUESTION NO 2 part B of this paper ---ughh frickin annoyin
http://papers.xtremepapers.com/CIE/...d AS Level/Chemistry (9701)/9701_w08_qp_4.pdf
Hey dude how are you ... Long time no see in tutions :p
So about ur question im gonna explain it to u even though it makes no sesnse at all

Look at step 1 ... a is for h2o2 b is for I- and c is for H+

In the first step h2o2 has appered once so right 1 in the first row of a
I- has appered one in the equation so put 1
And H+ is not there so put zero

For step 2 H2O2 is not there but still u have (1) in the first box so put another one because it was shown in the first step
For I- the same thing ..not shown in step 2 but u already has one from the spfirst step so put another 1
For hydrogen ion this time its shown in step 2 so put 1

For step 3
H2o2 u already has 1 from step 1 so put 1
I- is shown in step 3 and step 1 so put 2 because now u have 2 I- shown
H+ is shown in step 3 and step 2 so in total its shown twice so put 2

Thats it ..hope it hepls :)
 
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lol yeah i spent like 30 mins on this question figuring out why the mark scheme is saying the complete opposite and at the end i dont know why..i bet the examiner is a foolish inspector so he doesn't know these kind of stuff :p
come on...it is so clear.

Suspect 2 clearly, has similar fragments as crime scene 1
 
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ok guys a question..whoever gets it correct without cheating :p gets a free candy or a cookie ur choice

what is the test that will distinguish methanol from ethanol ?
 
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ok guys a question..whoever gets it correct without cheating :p gets a free candy or a cookie ur choice

what is the test that will distinguish methanol from ethanol ?
Using NaoH + I2 (iodine)
Ethanol gives yellow ppt and no rxn with methanol
 
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