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Chemistry Paper 5 | 17th of June | Notes and preparation

Hows Your preparation?

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Agent Z

Agent Z

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saifulahmed49 said:
The mass of 1 mol of chromium(III) sulfate (Cr2(SO4)3) is 392 g. Hence, for the
cell in the diagram to measure the standard electrode potential, 1 dm3 of the
chromium(III) sulfate solution used must contain

A 104 g of chromium(III) sulfate.
B 196 g of chromium(III) sulfate.
C 392 g of chromium(III) sulfate.
D 784 g of chromium(III) sulfate.

why is the answer B?
Click to expand...
I mol of Cr2(SO4)3 will have 2 moles of Cr whereas we just need 1 mole (standard conditions)
 
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