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Chemistry: Post your doubts here!

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1 chain has 2 double bond in residue and two chains contain single double bond in them thus the number of double bond saturated=5(9-4)
1 double bond require 1 mole of H2 so 5mol are require
Thankyou but I dont get it :'(
how did you get 9-4? :/
 
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Which formulae show propanone and propanal as different compounds?

A. Emperical, molecular, structural and displayed formulae.
B. Molecular, structural and displayed formulae.
C. Structural and displayed formulae only.
D. Displayed formulae only.

I think it's C. Can someone confirm this, please?
yes it is as only structured and display formula will show you the position of the bond
 
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The answer is D, this is because in enthalpy change of formation, or any enthalpy change...the reactants must be in their standard states, carbon exists as solid, while H2 is a gas. So the answer is either C or D. in the enthalpy changes the products formed are in gaseous state, so the answer is C. you mind telling the year so i can confirm the answer!

May/June 2011 Paper 9701/12, question 8. So... is it C or D? :p
 
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Thankyou but I dont get it :'(
how did you get 9-4? :/
in the orignal molecule there are 9 double bonds if you count them......................in the residue one chain hai 2 double bonds and 2chains have 1 double bond thus total is 4.....so the bonds that are saturated are 9-4=5


I HOPE YOU GET IT NOW
 
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in the orignal molecule there are 9 double bonds if you count them......................in the residue one chain hai 2 double bonds and 2chains have 1 double bond thus total is 4.....so the bonds that are saturated are 9-4=5


I HOPE YOU GET IT NOW
Yes I do!!
Thankyou so much!
but dont caps lock dude,sorry im a big explanation need-er :(
 
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How many isomers with the structure C5H10 have structures involving pi bonds?

A. 3
B. 4
C. 5
D. 6

Why?
 
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the equation is N2+3H2----->2NH3

in the start moles of H2=60......... at equlibrium H2 moles=48....thus change in moles=60-48=12

from the equation the ratio of H2:NH3=3:2...............thus moles of NH3 produced would be (2*12)/3=8moles.....
Mass=Mr*moles
Mass=(14+3)*8
Mass=17*8
Mass=136Kg
wait wait1 how'd you get the moles of H2 as 60 and 48?
 
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Hello how do you look for a chiral carbon atom in a cyclic or aromatic compound please? Thx :)
 
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